What magnification do you get with eyepieces having focal legths of: a.) 9mm, b.) 20mm and c.) 55mm? What is the telescopes angular resolution?
2006-10-18 14:54:50 · 5 answers · asked by mapleafgal sweet an delicious 1 in Science & Mathematics ➔ Astronomy & Space
Magnification = focal length of objective divided by focal length of eyepiece. 2m = 2,000mm, so the 9mm eyepiece gives 2,000/9 = 222 power, the 20mm gives 2,000/20 = 100 power and the 55mm gives 2,000/55 = 36 power.
2006-10-19 03:17:28 · answer #1 · answered by campbelp2002 7 · 0⤊ 0⤋
Kris has the right idea, but to be specific, you need to divide the mirror's focal length (2 m) by the eyepiece focal length to find the magnification.
2006-10-18 18:06:41 · answer #2 · answered by Anonymous · 0⤊ 0⤋
You can't tell what the focal length of a telescope might be from its aperture -- it could be anything. Without knowing the focal length I can't recommend eyepieces. 600mm is a very large telescope, and anyone owning one would KNOW what eyepieces work well with it.
2016-03-28 01:06:30 · answer #3 · answered by Anonymous · 0⤊ 0⤋
To find magnification, divide the two focal lengths (convert them to the same units first, though)
2006-10-18 14:58:47 · answer #4 · answered by kris 6 · 0⤊ 0⤋
kris has the correct answer for the magnification.
In order to get the angular resolution, use the Rayleigh Criteria which is approximated by:
sin(a) = 1.22 L/D
where a is the angular resolution, L is the wavelength of light being considered (for visible light one can usually use 550nm), and D is the diameter of the objective mirror.
Again make sure that the units of length are equivalent (I would convert them all to meters).
2006-10-18 16:06:22 · answer #5 · answered by Kevin R 2 · 0⤊ 0⤋