I have a test tomorrow and trying to figure out this review. I am confused.
In this table, x=size of family. The percentage data are percentages of US families of this size.
x=% 2=42% 3=23% 4=21% 5=10% 6=3% 7 or more=1%
a. What is the probability that a family selected at random will have only two members?
b. What is the probability that a family selected at random will have more than three members?
Thank for your help! THIS IS DIFFICULT STUFF!
2006-10-18 13:58:25 · 4 answers · asked by dogbite1562 1 in Education & Reference ➔ Homework Help
a 42%
b. 35%
this is not difficult stuff, if you tell your self that, you are not going to get anywhere
2006-10-18 14:03:59 · answer #1 · answered by Rainy 3 · 0⤊ 0⤋
the probability that a family selected at random will have only 2 members is 42%
The probability that a family selected at random will have more than 3 is 58-23=35%
I had to write it down on paper and add the numbers all together to figure it out.
Just looks tricky at first. Like the sock drawer question.
2006-10-18 14:12:05 · answer #2 · answered by Grev 4 · 0⤊ 0⤋
a. 42/100 which reduces down to 21/50 = 42%
b. add the rest of them and put it over a hundred 58/100 = 29/50 = 58%
2006-10-18 14:05:28 · answer #3 · answered by Anonymous · 0⤊ 0⤋
a. 42%
b. 35%
2006-10-18 14:00:41 · answer #4 · answered by Poncho Rio 4 · 0⤊ 0⤋