by+2 over 3 = c (solve for y)
my math teacher just taught us this and i still
dont get it
(looks at notes)
i so hate math
2006-10-18 12:51:41 · 6 answers · asked by car_crashhhhhhhh 1 in Science & Mathematics ➔ Mathematics
i'm guessing you mean (by+2)/3 = c
solving for y:
by+2=3c
by=3c-2
y=(3c-2)/b
2006-10-18 12:55:11 · answer #1 · answered by Ken 2 · 0⤊ 0⤋
Hi. Math CAN be fun. 'by' means 'b' times 'y', 'over' means divided by, 'c' is simply one side of the equation, with the '=' sign being the balance point. So whatever you do on one side you do on the other. You want 'y', right? Start by multiplying both sides by 3. (by+2 = 3c),
then subtract 2 from both sides (by = 3c-2), then divide both sides by 'b' (y=(3c-2)/b). I know it looks hard but the concept works for all equations. Learn the concept, learn that math is fun.
2006-10-18 19:56:01 · answer #2 · answered by Cirric 7 · 0⤊ 0⤋
Do you know the order of operations? PEMDAS, just do that, but always the opposite if you're moving something across the = sign.
2006-10-18 19:55:41 · answer #3 · answered by MattMan 3 · 0⤊ 0⤋
(by + 2) / 3 = c
multiply both sides by y
3by + 6 = cy
3by - cy = -6
factor
y(3b - c) = -6
y = (-6) / 3b - c
2006-10-18 19:58:03 · answer #4 · answered by Adam J 2 · 0⤊ 0⤋
(by + 2) / 3 = c
First, multiply both sides by (1y)
This is what you'll get
3b(1y) + 6 = cy
3b(1y) - cy = -6
factor this equarion to equal
1y(3b - c) = -6
Final answer ==> 1y = (-6) / 3b - c
2006-10-18 20:06:12 · answer #5 · answered by Kendall 1 · 0⤊ 0⤋
just solve for y
y=(c-2/3)/b
2006-10-18 19:54:26 · answer #6 · answered by Yue J 3 · 0⤊ 0⤋