I recently figured out that when hydrogen burns, it creates water(hence the name HYDROgen). So how much water was produced when the Hindenburg (the blimp) burned? Can you give me how you got the answer, too? equation, link, whatever.
2006-10-18 12:50:54 · 4 answers · asked by Anonymous in Arts & Humanities ➔ History
The Hindenberg contained 200,000 m³ (= 200,000 liters) of H2
PV = nRT, and so n = (PV)/(RT)
Let's assume the pressure was 1 atmosphere, the temperature was 25 C (298.15 K) and R = 0.0820574587 L · atm · K-1 · mol-1
Thus, n = (1 x 200,000)/(0.0820574587 x 298.15) = 8174.8 mol
H2 + 1/2O2 > H2O
Thus for every mole of hydrogen consumed, one mole of water is produced, and so 8174.8 moles of water was produced.
Since the mass of water is 18.01508 g/mole and the density of water is 1 g/mL, 8174.8 x 18.01508 = 147270 mL or 147 liters of water was produced by the complete combustion of 200,000 cubic meters of hydrogen.
2006-10-18 13:07:12 · answer #1 · answered by Steven Jay 4 · 3⤊ 0⤋
There was no water produced.
Wait, no. What the guy below me said.
2006-10-18 20:00:15 · answer #2 · answered by buzzfeedbrenny 5 · 0⤊ 0⤋
Not enough to extenguish the flames..
2006-10-18 19:55:48 · answer #3 · answered by Black Sabbath 6 · 0⤊ 0⤋
not enough to put out the fire, sorry I had to say that
2006-10-18 19:54:50 · answer #4 · answered by bayareart1 6 · 1⤊ 0⤋