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An insurance company issues life insurance policies in 3 separate categories: standard 50%, preferred 40%, and ultra-preferred 10%. Each standard, preferred and ultra-preferred policyholder has probability 0.010, 0.005 and 0.001 of dying in the next year, respectively. What is the probability that a policyholder dies in the next year?

2006-10-18 11:40:00 · 2 answers · asked by Tess 1 in Science & Mathematics Mathematics

2 answers

Odds of a standard policy & death: 0.5 * 0.01 = 0.005
Odds of a preferred policy & death: 0.4 * 0.005 = 0.002
Odds of an ultra-preferred policy & death: 0.1 * 0.001 = 0.0001

Add up the three probabilities, and you get 0.0071... or if you prefer the answer as a percentage, 0.71 percent.

2006-10-18 11:49:03 · answer #1 · answered by Bramblyspam 7 · 1 0

Given that each category is mutually exclusive then

P (policy holder dies) = 0.5*0.010 + 0.4*0.005 + 0.1*0.001
= 0.005 + 0.002 + 0.0001
= 0.0071

2006-10-18 11:57:44 · answer #2 · answered by Wal C 6 · 0 0

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