18xxx - 39xx - 15x
(xxx = x to the third)
2006-10-18 10:09:07 · 4 answers · asked by Zapped92 2 in Science & Mathematics ➔ Mathematics
Take the greatest common factor out of each term. In this case, it is 3x, because 3x goes evenly into each term. So you get 3x(6xx-13x-5). Then you factor 6xx-13x-5, which is a quadratic. That comes out to be (3x+1)(2x-5). So your fully factored form is
3x(3x+1)(2x-5)
2006-10-18 10:19:54 · answer #1 · answered by tamana 3 · 1⤊ 0⤋
Do the obvious first,
18x^3 - 39x^2 - 15x
x(18x^2 - 39 x - 15) Now, realize, 18, 39, and 15 all have 3 as a factor. So
3x(6x^2 - 13 x - 5) Then,
3x (3x +1 )(2x - 5 )
2006-10-18 17:52:16 · answer #2 · answered by danjlil_43515 4 · 0⤊ 0⤋
Using your notation...
Factor
18xxx - 39xx - 15x
equals
(3X)(3X + 1)(2X - 5)
done.
Regards,
Zahbudar
2006-10-18 17:17:02 · answer #3 · answered by zahbudar 6 · 0⤊ 0⤋
3x(x-1)(6x+5)
2006-10-18 17:14:12 · answer #4 · answered by 7 · 0⤊ 0⤋