For the equation x - 2 √x = 0, perform the following: solve for all values of x that satisfies the equation

Question

Give answer and show work.

Answer 1

x - 2rtx = 0

Add 2rtx to both sides

x = 2rtx

Divide both sides by 2

x/2 = rtx

To get rid of the square root, square both sides.

x^2 / 4 = x

Multiply by 4.

x^2 = 4x

Subtract 4x from both sides to get the equation equal to zero.

x^2 - 4x = 0

Factor out an x

x(x-4) = 0

Set each factor equal to zero and solve for x.

x = 0 and x-4 = 0

Hope this helps. Good Luck.

Answer 2

x - 2 √x = 0

x = 2 √x

Square both sides

x^2 = 4x
x^2 - 4x = 0
x(x - 4) = 0

x = 0, x = 4

When you square both sides of an equation, you might introduce a redundant root, so check all the results in the original equation

0 - 2√0 = 0
0 = 0

4 - 2√4 = 0
4 - 2*2 = 0
0 = 0

Hopefully I did it right.

Answer 3

x= 4

Answer 4

x - square root of x = 0....original equation
x = square root of x......plus square of x on both sides
x = {0,1}

0*0=0 0's square root is 0
1*1=1 1's square root is 1

Square root is use for numbers like x^2, y^2. So the only numbers that has the same value even it's multiplied on itself are 0 and 1 only. By the way, even though (-1) * (-1) =1, but it may not work in this equation.

Answer 5

x - 2 √x = 0
x=2√x
x^2=4x
x=4

Answer 6

set x = 2* x^1/2 to solve

square both sides to get: x^2 = 4x

The only answer that works here is x=4

Answer 7

x = 2√x
x² = 4x
x² - 4x = 0
x(x-4) = 0
x = 0
x = 4