What is the molecular, ionic, and net ionic equation?

Question

Ammonium sulfide with silver nitrate?




Please write out how you got it!

Answer 1

Ammonium sulfide is (NH4)2S (Note the 4 and 2 are subscripts) This is found by knowing the ammonium ion is NH4 and that is has a +1 charge. The sulfide ion, S, has a -2 charge...therefore it takes 2 ammonium ions for every 1 sulfide ions.

Silver nitrate is Ag(NO3) (The 3 is a subscript.) Ag has a +1 charge and NO3 has a -1 charge.

The molecular equation is (NH4)2S + 2Ag(NO3) ---> 2NH4(NO3) + Ag2S

If you remember the charges that makes sense...you also have to balance the equation. which is why there is a 2 in front of silver nitrate and in front of ammonium nitrate so that there are the same number of molecules/ions on each side.

The ionic equation is when you break down the ions and add them all together, like so:

2NH4(+1) + S(-2) +2Ag(+1) + NO3(-1)---> 2NH4(+1) + NO3(-1) + 2Ag(+1) + S(-2)

To get the net ionic equation cancel out the ions that are the same on both sides and write what you have left. In this case...all the ions cancel out...if the reactants were aqueous(dissolved in water). You didn't specify...if one of those is a solid, then you have to write the states...and a solid cannot be split up into ions, so that will affect your net ionic equation.