PLease help!!! Find dy/dx for each of the following?

Question

(a) x=3t^2, y=2t at t=2
(b) x=sin^20 y=cos0sin0 at 0=pi/6
(c) x=2t^3 y=2/t^2 at t=2

need to show workings. I'm really stuck

thanks

For the first one that exact question I was given was find dy/dx
x=3t^2
y=2t
at t =2. We are supposed to figure out what rule to use. I'm totally lost

Answer 1

a) dx/dt = 6t dy/dt = 2 and now dy/dx = (dy/dt) / (dx/dt) = 2/(6t)
= 1/(3t)... for t=2 we have dy/dx = 1/(3.2) = 1/6

b) dx/do = 2sin(o)cos(o) dy/do = -sin(o).sin(o) + cos(o).cos(0)

and now dy/dx = (-sin(o)sin(o) + cos(o)cos(o))/(2sin(o)cos(o))

after trigonometric transformations we get cos(2o)/sin(2o) =
cot(2o) .... for o=pi/6 .... cot(pi/3) = 1/sqrt(3)

c) dx/dt = 6t^2 dy/dt = -4/t^3 and now dy/dx = -2/(3t^5)
and for t = 2 we have -1/48

Answer 2

You may be stuck because you don't understand what you are being asked to do. I don't understand either. You are asking for dy/dx and there is no function y=f(x) Clarify the problem and I'll help,

Answer 3

are you doing chainrule? or related rates? or what kind of problems?