math problem solving?

Question

bill and joe found 14 marbles, bill found 4 more then joe, how much did each one found?

show me how you came to the answer.

Answer 1

j is joe
b is bill
j +j+4=14
2j=10
j=5
b=9

j

Answer 2

Let x= Joe's marbles
So since Bill found 4 more, Let x+4=Bill's marbles

All together, they add up to 14, so

x+ x+4=14
2x+4=14

Subtracting 4 from both sides:
2x=10

Dividing both sides by 2:
x=5

Since x=Joe's marbles, and x=5, Joe found 4 marbles.
x+4=Bill's marbles, 5+4=9 So Bill found 9 marbles.

Answer 3

bill found 9 and joe found 5 because if bill found 4 more then joe subtract 4 from the total then u just divide the remaing 10 in half to get 5 each then u add the 4 to bill

Answer 4

joe the number of marbles is x, bill is x+4
x+ (x+4)=14
2x+4=14
2x=10
x=5 (joe)
x+4=9(bill)

Answer 5

let us suppose joe found x marbles.
therefore bill found x+4 marbles.
now, according to the given problem:
x+(x+4)=14
2x+4=14
2x=10
x=5
so joe found 5 and bill found 9 marbles.

Answer 6

let
x = j0e
bill = 4+x (because bill f0und 4 m0re than j0e)

x+4+x=14

2x=14-4

2x=10

x=5

j0e g0t 5 marbles while bill g0t 9!=)

Answer 7

BILL+(BILL+4)=14
2 BILL =14-4
BILL=10/2
BILL=5


So bill is having 5 and joe is having 9. Total is 14.

Answer 8

9 marbles