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(6_2)_8_9_1=13?

What are the operators in this equation

2006-10-18 06:28:57 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

6 answers

(6x2)-8+9x1=13

2006-10-18 06:31:22 · answer #1 · answered by poorcocoboiboi 6 · 1⤊ 0⤋

(6*2)-8+9*1=13

2006-10-18 13:32:12 · answer #2 · answered by harleychic 4 · 0⤊ 0⤋

(6*2)=12
12-8=4
4+9=13
13*1=13
12-8+9*1=13

2006-10-18 13:41:21 · answer #3 · answered by collegegirl 2 · 0⤊ 0⤋

2 answers:
(6x2)-8+9x1=13
(6x2)-8+9/1=13

2006-10-18 13:39:36 · answer #4 · answered by smarties 6 · 0⤊ 0⤋

(6x2)-8+9x1=13

2006-10-18 13:37:46 · answer #5 · answered by Anonymous · 0⤊ 0⤋

I have no idea!

2006-10-18 13:32:14 · answer #6 · answered by pollywollydoda 3 · 0⤊ 0⤋

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