4x^2-8x+3=5
2006-10-18 05:49:27 · 4 answers · asked by Marie 3 in Education & Reference ➔ Homework Help
Be more specific on what you need to do with the equation. If you want to simplify this:
4x^2-8x+3-5 = 5-5
4x^2-8x-2 = 0
2 (2x^2-4x-1) = 0
2006-10-18 05:53:40 · answer #1 · answered by jard jard binx 3 · 0⤊ 0⤋
I assume you want to solve the equation. Have you had the quadratic formula yet? If not, then you will have to be able to use factoring or completing the square. Let's see.
Move the 5 to the right side.
4x^2 - 8x - 2 = 0 (standard form for a quadratic equation)
Factor out a 2.
2(2x^2 - 4x - 1) = 0
2x^2 - 4x -1 is not factorable. Assuming you have the quadratic formula, then use it for the equation
4x^2 -8x - 2 = 0. I will let you do that.
2006-10-18 14:40:39 · answer #2 · answered by LARRY R 4 · 0⤊ 0⤋
I will assume that you want to factor:
4x^2-8x+3-5=0
4x^2-8x-2=0
2x^2-4x-1=0
2006-10-18 12:56:44 · answer #3 · answered by odu83 7 · 0⤊ 0⤋
Specify what is to be done...factorisation or solving an equation
2006-10-18 13:19:54 · answer #4 · answered by alpha 7 · 0⤊ 0⤋