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No. Because of conservation of angular momentum (L = r X p; where the X indicates a vector cross product). From this relationship, we can see when r, the radius of the orbit, is decreased, p, the linear momentum, has to increase. p = mv; where m is the mass of the electron and v is its velocity tangent to the orbital revolution at a distance r.

So we have R X p = r X P from the conservation of angular momentum; where R > r and P > p for an electron with mass m at two different orbits (R and r). Assuming the angle between R and p, and the angle between r and P are the same, we can write Rp = rP, which are scalers; so that P = Rp/r.

P = Rp/r clearly shows that a closer orbit (r) requires a greater linear momentum (P) to offset the smaller orbit. But P = mWr and p = mwR; where the w and W are angular velocities, so that P = mWr = Rp/r = RmwR/r and Wr^2 = wR^2 so that W = w(R/r)^2. This last relationship simply says angular velocity of a smaller orbit (r) has to be greater than that same electron's angular velocity at a greater orbit (R).

Note that (R/r) is squared. This means, for example, that cutting an orbit distance in half will cause the angular velocity to quadruple over its initial rate. This also means that the kinetic energy of the electron in the closer orbit will be four times that same electron at the farther orbit.

PS: All the above is based on nonquantum physics, which was taught before the 1960's. In quantum physics, momentum and location are less certain. That is, when fixing a quantum's location, we are uncertain about it momentum...and vice versa. This is called the Heisenberg Uncertainty Principle.

2006-10-18 06:25:44 · answer #1 · answered by oldprof 7 · 0 0

angular velocity isn't really used much. Due to the uncertainty principle we can't really pin down how fast an electron is going and what the radius of curvature in it's orbit is. We do use angular momentum a lot. This is the quantum number, l. It is a conservative quantity and can only be 0 for an s orbital, or -1, 0, +1 for the p-orbital of a hydrogen atom. The different orbitals are defined partly by their angular quantum number. There is also the magnetic spin number, m, an intiger which varies from +/- l.

2006-10-18 06:06:01 · answer #2 · answered by bordag 3 · 0 0

i don't undergo in innovations if it become Bohr or not that did the Auf Bua concept yet i think of which would be what you're speaking approximately. With the introduction of quantum concept they think of that an electron could be in simple terms approximately everywhere at one ingredient in time - ex: it must be here or it must be on Mars. although, the two theories are linked interior the reality they believe that electrons have distinctive capability stages and that the valence electrons are the source of molecular bonding. IE: Carbon could have -4 fee or a +4 fee. Hydrogen has a +a million fee mutually as Oxygen has a -2 fee. Atoms look happy whilst the outer capability point is finished. for greater concepts in this seek for suggestion from a periodic table.

2016-11-23 17:43:06 · answer #3 · answered by Anonymous · 0 0

Hi. The conservation of angular momentum dictates how an electron moves.

2006-10-18 05:35:29 · answer #4 · answered by Cirric 7 · 0 0

no the electron doesn't moves in the same angular velocity.

2006-10-18 05:57:15 · answer #5 · answered by rabah a 1 · 0 0

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