Find the derivative of each, Do not simplify
2006-10-18 04:44:30 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Its not really fair you just putting your homework questions on here, Allison.
See me after class.
2006-10-18 04:53:29 · answer #1 · answered by Stuart T 3 · 0⤊ 0⤋
y = 2/(3x^3 + x)^5/2
= 2(3x^3 + x)^-5/2
Let (3x^3 + x) = t
dt/dx = 9x^2 + 1
y = 2t^-5/2
dy/dt = -5t^-7/2
therefore,
dy/dx = dy/dt*dt/dx
hence,
dy/dx = -5(3x^3 + x)^5/2^-7/2*(9x^2 + 1)
2006-10-18 05:54:44 · answer #2 · answered by Aazib A 1 · 0⤊ 0⤋
y = 2/(3x^3 + x)^5/2
= 2(3x^3 + x)^-5/2
Let (3x^3 + x) = t
dt/dx = 9x^2 + 1
y = 2t^-5/2
dy/dt = -5t^-7/2
therefore,
dy/dx = dy/dt*dt/dx
hence,
dy/dx = -5(3x^3 + x)^5/2^-7/2*(9x^2 + 1)
2006-10-18 05:53:39 · answer #3 · answered by aazib_1 3 · 0⤊ 0⤋
low d high minus high d low over low squared
2006-10-18 05:08:17 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋