Find the derivative y^1 of each by the power rule
2006-10-18 04:02:21 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The power rule: d(x^n)/dx = nx^(n-1) unless n=0, in which case its just the same as taking the derivative of a constant.
So if that's not a big enough hint, I'm not sure what is. Fact is that expression is easily simplified, just think back to your algebra days. just to tidy things up just make sure you note the function will not have a derivative at x=0, (since your dividing by x^2)
2006-10-18 04:09:29 · answer #1 · answered by Jay 3 · 0⤊ 0⤋
Uhhh...2+2=5.
2006-10-18 11:05:56 · answer #2 · answered by Harry Manback 2 · 0⤊ 1⤋
if y = x^5 + (3x^3)/x^2,
y' = 5y^4 + 3
or
if y=(x^5 + 3x^3)/x^2),
y' = 3x^2 + 3,
(I simplified before taking the derivative--fewer steps & less chance of error)
2006-10-18 11:23:50 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
1 plus 1 equals 2.
2006-10-18 11:11:41 · answer #4 · answered by demsareidiots 3 · 0⤊ 1⤋
you dont mean y^1, you mean y'
and the power rule is that (ax^b)' = bax^(b-1)
Good luck!
2006-10-18 11:07:58 · answer #5 · answered by Stuart T 3 · 0⤊ 0⤋
answer is 0, i did this in my head!
2006-10-18 11:08:56 · answer #6 · answered by internetsurferbrowser 1 · 0⤊ 1⤋
5X^4-9X^2-2
2006-10-18 11:11:23 · answer #7 · answered by Anonymous · 0⤊ 1⤋