simplifly (y/x^3z^2) x sqrt(9z^11/y^2?

Answer 1

confused, sorry

Answer 2

You wrote, (y/x^3z^2) x sqrt(9z^11/y^2).

I'm assuming the middle "x" means to multiply and not the "x" in the algebra as I can clearly see how you spaced out this character between the two terms.

Then, simplifying only the sqrt term we get.

y/(x^3.z^2) . 3z^(11/2)/y

y's cancel out and we get.

3z^(11/2) / (x^3.z^2)

For the z term minus 2 from 11/2 to get 7/2 in the index.

3z^(7/2) / (x^3)

I didn't check this fully it's just a quick scribble down. To verify if it's correct just substitute some simple numbers into x, y and z then compare the 3z^(7/2) / (x^3) with (y/x^3z^2) . sqrt(9z^11/y^2).

Answer 3

sqrt 9z^11 / y^2

Is the same as taking the sqrt of the top and the bottom.

sqrt 9z^11 = sqrt (9 * z^8 * z^2 * z) = 3z^5 sqrt (z)

The sqrt of y^2 is y

So we have:

(y / x^3 z^2) x (3z^5 sqrt z / y)

Now, multiply:

The "y's" cancel, and the z^2 will cancel as well.

3z^5 x^3 sqrt z