A slow bowler bowls the ball. The facing batsman hits the ball back towards the wicket at the non-striker's end on the full. The bowler dives across to catch the ball. Before the bowler clasps the ball, the force of the ball pushes the bowler's hand onto the wicket at the non-striker's end (the ball is in contact with the bowler's hand when this happens) and the wicket is broken. The non-striker is backing up, and is out of his crease at this time. The bowler does clasp and catch the ball on the full. So, who is out? Is the non-striker out "run out" or is the batsman out "caught". Of course there is no double-play in cricket. Once a wicket is taken, the ball is dead!
2006-10-18 00:03:15 · 10 answers · asked by Mez 6 in Sports ➔ Cricket
There's no doubt in my mind that if this ever occurred, the umpires would decide that the striker is out caught (whether that's technically correct is another question). While it's theoretically true that the fielder has to hold the ball for a fixed period of time, we've seen many times games where the fielder throws the ball in the air to celebrate a catch, or even throws it to the ground or over the boundary, and has still been given out, even when the batsmen have tried to argue the rule. Umpires have universally interpreted the rule as 'the fielder must demonstrably have control of the ball', and that's why I'm sure that any umpire would give the striker out caught in this situation.
If the fielding side desperately wanted the other batsman out, they could *try* deliberately dropping the ball after breaking the stumps, but any decent umpire wouldn't stand for that kind of nonsense.
2006-10-20 04:55:16 · answer #1 · answered by MC Kiwi 2 · 0⤊ 0⤋
Ok for the person who said the ball doesn't touch the stumps - that doesn't matter. If the ball is in the hand, and the hand breaks the wicket, it is still out. This is how keepers can get away with stumpings with the ball inside their gloves.
However, if the catch is taken, it has happened first, as the ball hits his hand before the stump is broken, so the STRIKER would be out if this extra-ordinary thing ever happened.
2006-10-18 01:00:49 · answer #2 · answered by Anonymous · 0⤊ 0⤋
For a catch to be given as out , the ball must be deemed "under control" (in other words it must be clutched) and not simply in the palm of the hand..so under those circumstances the non-striking batsman must be given out if the bowler's hand hits the wicket at his end with the force of the ball behind it.
2006-10-18 01:26:44 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the batsman at the non-striker's end will be out cuz the ball is considered to be caught only after it remains for 2 seconds in the catcher's hands but in this case the ball is first hitting the wickets and not caught!
2006-10-18 06:49:23 · answer #4 · answered by aki 4 · 0⤊ 1⤋
The batsman at the non-stricker going to out. since bowler doesnt took the catch (he toches his hand to wicket). So batsman on striker end will be safe.
2006-10-18 00:09:38 · answer #5 · answered by Munib 2 · 0⤊ 0⤋
time is to be considered there...
if ball in the bowler hand for 3 Min's
striker will out..
before that stump broken non-striker will out
2006-10-18 02:08:07 · answer #6 · answered by navaneeth 1 · 0⤊ 0⤋
Sachin Tendulkar is the batsman who wastes most of the deliveries bowled to him when he is 90+ but less than 100. He has had the record of 13 outs in the nervous nintees. Virender Shewag however doesn't care and plays his natural game. However the above may vary depending upon the varying condition.At times a lion can be a mouse and vice versa. Just the same way depending on the required run rate, the above mentioned condition may vary.
2016-03-28 14:14:18 · answer #7 · answered by Anonymous · 0⤊ 0⤋
the batter on strike is out the ball never made contact with the stumps
2006-10-18 00:15:28 · answer #8 · answered by SociallyAwkwardPenguin 5 · 0⤊ 0⤋
non-striker
2006-10-18 00:20:55 · answer #9 · answered by Rocky D 2 · 0⤊ 0⤋
non-stricker will be out
2006-10-18 00:14:12 · answer #10 · answered by Pokkiri 3 · 0⤊ 0⤋