she was given this sequence of numbers
1
8
27
64
she was asked to find the next 4 numbers of the sequence and how she came by her answers.
It took me 2 hrs to figure it out!!!!
2006-10-17 23:52:36 · 31 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
with all due respect to the people who are having a go and calling this person stupid....i find that pathetic. i am crap at maths, and it took me ages to understand the answers, let alone the question. i run my own business (have an accountant!!) some people have a brain for maths, and people are better at another subject.
2006-10-18 00:11:56 · answer #1 · answered by lil missy 2 · 2⤊ 0⤋
Maybe you were tired, if you took 2 hours. By investigation, in less than a minute, I could see that the sequence is the cube of the consecutive numbers 1 thru 4. So the next 4 numbers would be 5^3,6^3,7^3,8^3 or 125, 216, 343, 512.
By reading the answers to math questions at yahoo, sometimes I'm amazed at how others can find simple solutions to what appeared to me as complicated problems. So don't be dismayed if you took 2 hours while others may take just a few seconds to figure out the solution to this sequence problem.
2006-10-18 12:33:01 · answer #2 · answered by tul b 3 · 1⤊ 0⤋
This is a standard sequence-the cube numbers.
1 x 1 x 1 = 1
2 x 2 x 2 = 8
3 x 3 x 3 = 27 and so on.
After 64, 125, 216, 343, 512
Your daughter would be well advised to learn and remember the first few terms of this sequence-it comes up a lot in GCSE Maths. Look up also square numbers and triangle numbers.
2006-10-18 10:05:03 · answer #3 · answered by astephens29 3 · 1⤊ 0⤋
these are the cubes (3rd power) of the integers.
1*1*1=1, 2*2*2=8, 3*3*3=29, 4*4*4=64
so the series continues:
5*5*5=125, 6*6*6=216, 7*7*7=343, 8*8*8=512
it took me 1 minute and I didn't even use a calculator ;-)
there is nothing in this that seems too tough for a 12 year old. But maybe our expectations of the school system are so low, that we now start to wonder?
2006-10-18 08:36:48 · answer #4 · answered by AntoineBachmann 5 · 0⤊ 0⤋
In context this problem is not as difficult as it first appears.
I am sure that the class were learning sequences at the time and had most likely covered various different sequences in class.
I know that there were already answers posted when I was looking at the problem, although I can assure you i did not cheat. I think it took about 10 seconds to work it out.
5 cubed - 125
6 cubed - 216
7 cubed - 343
8 cubed - 512
The working is that:
1 = 1 cubed
8 = 2 cubed
27 = 3 cubed
64 = 4 cubed
Just wait until they start complex sequences!
2006-10-18 07:05:56 · answer #5 · answered by advent m 3 · 1⤊ 0⤋
It's just the cubic numbers
1 * 1 * 1 = 1
2 * 2 * 2 = 8
3 * 3 * 3 = 27
4 * 4 * 4 = 64
5 * 5 * 5 = 125
6 * 6 * 6 = 216
7 * 7 * 7 = 343
8 * 8 * 8 = 512
etc.
2006-10-18 07:01:00 · answer #6 · answered by JM 1 · 1⤊ 0⤋
cube series
1 = 1^3
8 = 2^3
27 = 3^3
64 = 4^3
therefore the next 4 sequence will be:
5 ^3 6^3 7^3 and 8^3
therefore,
125, 216, 343, 512
good luck =)
2006-10-18 08:37:49 · answer #7 · answered by Anonymous · 1⤊ 0⤋
Right, they are all cube numbers, the same as square numbers, just multiplied again.
1*1*1=1
2*2*2=8
3*3*3=27
4*4*4=64
5*5*5=125
6*6*6=216
7*7*7=343
8*8*8=512
2006-10-18 11:46:13 · answer #8 · answered by Matthew H 2 · 1⤊ 0⤋
this is a cube series
1 = 1^3
8 = 2^3
27 = 3^3
64 = 4^3
next 4 numbers are
5^3=125
6^3=216
7^3=343
8^3=512
2006-10-18 06:58:09 · answer #9 · answered by The Potter Boy 3 · 2⤊ 0⤋
Next 4 numbers are 125,216,343,512. We observe that the numbers represent the series x^3 ,x=1...to n
2006-10-18 07:07:25 · answer #10 · answered by openpsychy 6 · 1⤊ 0⤋