how do you identify spectator ions in redox equations?

Question

I understand everything about redox equations like oxidation and reduction how to balance them. Balance the electrons and balance them in acidic and basic solution. But how do you identify spectator ions? Like I know that when an element such as Na is attached to dichromate =
Na2Cr2O7 -2 we must eliminate the Na. I know this but how about this problem:
AuCl3 + NaI > Au + I2 + NaCl

my teacher eliminated all Cl and Na
so AU + I > Au + I2 (why??? eliminate Na and Cl is it because they dont change oxidation states in the reaction???)

why does this occur? ANY help please would be great.

Answer 1

Since the Na and the Cl are in aqueous solutions on both sides of the equation, they are just "floating around" as ions in the solution, and don't really react - hence they are called "spectators" and can be negated.

Answer 2

initially double displacement reactions do not undertake redox reaction assign the oxidation form to be certain the oxidized one, perceive the only that won rates occasion interior the reactant ingredient the oxidation form of nitrogen is +2 and then interior the product ingredient it became +4 it ability it quite is the only that oxidized. the only that decreased is the only lose +fee occasion interior the reactant ingredient the oxidation form of nitrogen is +2 and then interior the product ingredient it became +a million it ability it quite is the only that decreased the spectator ion is the only that failed to alter

Answer 3

look at it like this, the Na and Cl are not changed in the reaction...thus, they are just along for the ride, watching the show, like spectators. you are correct in your assumption.

Answer 4

No change to them, means they are not directly involved in the reaction... For Ionic equations, we are only concerned about those ions that are really in the reactions.

Answer 5

they are usually drinking beer and wearing shirts supporting the event.

chemistry the ultimate spectator sport.