how much energy (kJ) is dissipated by the radiator per minute if....?

Question

The radiator in your car uses either water or ethylene glycol (anti-freeze) to remove heat from the engine and dissipate it to the outside air. If the water recirculation rate is 20.0 kg per minute and the water temperature leaving the engine and entering the radiator is 98.0 C and the temperature of the water leaving the radiator and entering the engine is 45.0 C

Answer 1

20kg of water dropped from 98ºC to 45ºC contains heat energy of

cp*20*10^3*(98-45),

where cp is the specific heat of water = 4.18 joule/gºC; for ethylene glycol cp = 2.41 joule/gºC