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2 answers

You always work from the inside out with double integrals. The previous answer is wrong.

Integrate first with respect to y. Since there are no y terms, this is just like a constant, and you'll get (sqrt(x^3)+1)y evaluated from 0 to x^2. This yields x^2(sqrt(x^3))+x^2. Integrate this with respect to x, from 0 to 1. This can be done with a u-substitution.

2006-10-18 04:51:52 · answer #1 · answered by zex20913 5 · 0 0

first integrate with resoect to x. and fill in the upper and lower boubds in x ( these are 0 - y

next integrate with respect to y and fill in the lower and upper bounds 0 and 1.

2006-10-17 17:41:42 · answer #2 · answered by gjmb1960 7 · 0 1

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