log(base 12)6x+log(base12)4x=2?

Question

solve for x

Answer 1

log(base 12)6x+log(base12)4x=2
log(base 12) (6x*4x) = 2
log(base 12) (24x^2) = 2
24x^2 = 12^2
24x^2 = 144
x^2 = 144/24
x^2 = 6
x = sqrt(6)
Note: You exclude -sqrt(6) because you cannot take the log of a negative number.

Answer 2

log(base 12)6x+log(base12)4x=2

=> log (base12) 6x*4x=2=> log(base12) 24x^2=2

24x^2 = 12*12 (since x^a =b=> log (basex)b=a)

x^2= 6 => x= squart of 6

ther fore x= squart of 6

Answer 3

log a + log b = log ab
log(base 12)(6x*4x) = 2
exponentiate:
24x^2 = 12^2 = 144
x^2 = 6
x = √6

Answer 4

i'm uncertain what you advise by utilising capacity of "ingredient" 4/X+5 = X/x+3 and that i anticipate x and X are distinctive So i've got have been given tried this..... 4/X+5 = X/x+3 4(x+3) = X(X+5) 4x+12 = X^2 + 5X 0 = X^2 + 5X -(4x+12)

Answer 5

since all logs are base 12 I won't bother indicating it below

to give you more practice working with logs, i'll do it this way

log 6x + log 4x = 2
log (6x * 4x) =2
log (24x^2)=2
log (12*2*x^2)=2
log 12 + log 2 + 2logx =2
1 + log 2 + 2logx =2
logx = (1 - log 2)/2 = (log 12 - log 2)/2 = [log (12/2)]/2 = log(6)/2
log x = log [6^(1/2)]
x = 6^(1/2)
x = square root of 6

Answer 6

log base (12)24x^2=2
24x^2=12^2
x^2=12*12/24=6
x=rt6

Answer 7

log(base 12)6x+log(base12)4x=2

log_2(6x*4x)=2
log_12(24x^2=2
log_12(2)+log_12(12)+logx^2=2
log_12(x^2) +log_12(2)=2-1=1
log_12(2x^2)=1
2x^2=12
x^2=6
x=sqrt(6)=2.449

Answer 8

log(base 12)6x+log(base12)4x=2

This expression equals:

ln(6x) / ln(12) + ln(4x) / ln(12) = 2

ln(6x) + ln(4x) = 2 * ln(12)
ln(24x^2) = 2 * ln(12)
e^ [ ln(24x^2) ] = e^ [ 2 * ln(12) ]
24 * x^2 = 144
x^2 = 6
x = +/- sqrt(6)

Remember:

ln(A) + ln(B) = ln(A*B)
2*ln(A) = ln(A^2)

Answer 9

Try the product rule...
log_12 (6x)(4x) = 2

Then convert to exponential notation...
24x^2 = 12^2

Use your algebra skills to finish it.

Answer 10

if you do 12 to the whatever power then the answer should be 72/5