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Calculate the pH of the solution resulting from the addition of 30.0 mL of 0.15 M NaOH to 75 mL of 0.80 M HCN solution. [Ka = 4.9x10^-10 for HCN.]

A) 8.22
B) 3.60
C) 10.40
D) 8.18
E) 8.15

okay I keep getting 8.2, must be a sig fig problem, what do you guys get?

2006-10-17 16:44:33 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

a

2006-10-17 16:59:32 · answer #1 · answered by Ask, and it shall be answered~ 3 · 0 0

i'm getting 12.22 :S. If (for some unusual reason, nevertheless my uni chem textbook has executed this a pair of cases) you anticipate that the addition of the NaOH doesnt impact the quantity (as quickly as lower back, i can't see why, yet I even have seen it executed) then i'm getting 11.3. the only thank you to get an answer off that checklist is that if u use 10mL because of the fact the quantity :S. and that's for e) 13.0 does all human beings else have any clue? undesirable question?

2016-11-23 17:01:24 · answer #2 · answered by Anonymous · 0 0

just remember that the digits in front of the decimal don't count towards sig figs for the pH. So, if there are 2 sig figs then there should be 2 digits after the decimal. 8.22 is the answer I got if that helps

2006-10-17 16:51:10 · answer #3 · answered by Greg G 5 · 0 0

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