An airplane is flying at a speed of 250 mph at an altitude of 4 mi. The plane passes directly above a radar station at time = 0.
What is the distance between the plane and the radar station after 5 minutes?
2006-10-17 16:11:59 · 16 answers · asked by cam1560 3 in Science & Mathematics ➔ Mathematics
After 5 minutes, the plane would have travelled
(250)(5/60)
(250)(1/12)
20.83 miles
However, the 4 mile altitude must be taken into calculations as well.
Using the pythagorean theorem or its derivative the distance formula, you have:
d = Square Root of (20.83 ^ 2 + 4 ^ 2)
d = Sqaure Root of (433.89 + 16)
d = Sqaure Root of (449.89)
d = about 21.21
2006-10-17 16:27:26 · answer #1 · answered by jackalrama 2 · 0⤊ 0⤋
I'm still trying to figure it out, and I'll post the answer when/if I get it, but the key is SOHCAHTOA.
You have two sides of the triangle formed: The 4 miles between the radar station and the plane's height, and the 20.93 miles the plane has travelled since passing the radar station. You're now trying to find the hypotneuse. Give me a minute, and I'll have it for you.
2006-10-17 16:17:16 · answer #2 · answered by Aliza, Queen of the Night 3 · 0⤊ 0⤋
speed = miles mins
250 60
x 5
thus x = 5 * 250/ 60 = 20.83
now base = 20.83
Ht = 4
the hyp = sqrt (ht^2 + base ^2)
= sqrt (16 + 433.889)
= 21.2105miles
so hyp is the distance after 5 mins
2006-10-17 16:44:21 · answer #3 · answered by nanduri p 2 · 0⤊ 0⤋
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2016-10-19 22:07:57 · answer #4 · answered by genthner 4 · 0⤊ 0⤋
About 21.205 miles. It's right. The sides of the triangle are:
Top (a) = 20.83 miles
Side (b) = 4 miles
Hypoteneuse (c) = 21.2105 miles
:)
2006-10-17 16:32:45 · answer #5 · answered by NYC Tim 2 · 0⤊ 0⤋
10 miles
2006-10-17 16:14:11 · answer #6 · answered by earthgoddess777 3 · 0⤊ 0⤋
21 miles
2006-10-17 16:19:34 · answer #7 · answered by KO 3 · 0⤊ 0⤋
The plane is green
2006-10-17 16:29:30 · answer #8 · answered by Anonymous · 0⤊ 1⤋
Use the Pythagorean Theorem. Google it and do the math.
2006-10-17 16:16:48 · answer #9 · answered by Anonymous · 1⤊ 0⤋
((125/6)^(2) + (4)^(2))^(1/2)
((125/6)^2 + (24/6)^2)^(1/2)
(15625/36 + 576/36)^(1/2)
(16201/36)^(1/2)
approx 21.21 miles
2006-10-17 16:32:23 · answer #10 · answered by frothel 1 · 0⤊ 0⤋