2006-10-17 16:10:57 · 5 answers · asked by E A 1 in Science & Mathematics ➔ Mathematics
2
Aloha
2006-10-17 16:14:13 · answer #1 · answered by Anonymous · 0⤊ 2⤋
To figure the lowest common multiple (i.e. the number that is a multiple of 120, 450 and 1500) it helps to figure the prime factorization.
120/2 = 60
60/2 = 30
30/2 = 15
15/3 = 5
5/5 = 1
So, 120 = 2 x 2 x 2 x 3 x 5
450/2 = 225
225/3 = 75
75/3 = 25
25/5 = 5
5/5 = 1
So, 450 = 2 x 3 x 3 x 5 x 5
1500/2 = 750
750/2 = 375
375/3 = 125
125/5 = 25
25/5 = 5
5/5 = 1
So, 1500 = 2 x 2 x 3 x 5 x 5 x 5
120 = 2 x 2 x 2 x 3 x 5
450 = 2 x 3 x 3 x 5 x 5
1500 = 2 x 2 x 3 x 5 x 5 x 5
Now look at each prime factor. Found the maximum number of times it appears for one of the numbers and take that.
We need 2 x 2 x 2 (from 120)
We need 3 x 3 (from 450)
We need 5 x 5 x 5 (from 1500)
So the lowest common multiple is 2 x 2 x 2 x 3 x 3 x 5 x 5 x 5
That works out to 10 x 10 x 10 x 9 = 9000
So the LCM( 120, 450, 1500 ) = 9000
2006-10-17 20:37:31 · answer #2 · answered by Puzzling 7 · 0⤊ 0⤋
9000
2006-10-17 16:19:12 · answer #3 · answered by cmadame 3 · 0⤊ 0⤋
120 = 4x3x10 = 2x2x2x3x5
450 = 2x5x5x9 = 2x3x3x5x5
1400 = 10x10x2x7 = 2x5x2x5x2x7 = 2x2x2x5x5x7
LCM = 2x2x2x3x3x5x5x7
= 8x9x25x7
= 12,600
2006-10-17 16:16:42 · answer #4 · answered by jg 2 · 0⤊ 0⤋
9000
I think.
2006-10-17 16:14:15 · answer #5 · answered by jackalrama 2 · 0⤊ 0⤋