2/(x+7)(x-5) + 5/(x+7)(x+6)?

Answer 1

who is our tacher i think im in your class....

Answer 2

You need to find the LCD here

so (x+7) is found in both parts, but the (x-5) and the (x+6) differ, therefore we multiply the 2 by (x+6)/(x+6) which of course equals 1, so nothing has changed

Likewise, multiply 5 by (x-5)/(x-5) which again, equals 1.

The resulting equation now looks like

[2(x+6)]/[(x+7)(x+6)(x-5)] + [5(x-5)]/[(x+7)(x+6)(x-5)]

With the LCD established and the denominators equivalent, combine the parts

[2(x+6) + 5(x-5)] / [(x+7)(x+6)(x-5)]

The numerator results in the following:

(2x+12) + (5x-25) = 7x - 13

so (7x - 13) / [(x+7)(x+6)(x-5)]

Don't know if you need the denominator reduced or not, but that will take more time than I am willing to devote, so I hope this gets you where you need to be.

Answer 3

2/(x+7)(x-5) + 5/(x+7)(x+6)

taking LCM

=>(2(x+6) + 5(x-5)) / (x-5)(x+6)(x+7)
=>(2x+12+5x-25)/(x-5)(x+6)(x+7)
=>(7x-13)/(x-5)(x+6)(x+7)

Answer 4

= [2(x+6) + 5(x-5)]/[(x+7)(x+6)(x-5)]

= [2x + 12 +5x -25]/[(x+7)(x+6)(x-5)]

=[7x - 13]/[(x+7)(x+6)(x-5)]

Answer 5

(2x+14 times 2x +10) + (5x+35 times 5x +42)
(4x +140) + (10x + 77)
(14x + 217) <-- Answer

Thats my guess using distribitive property. Good luck hope its right!
I hate algebra!

Answer 6

7/(x^4+15x+7)

Answer 7

I worked out the problem... click on the link to see my actual work, lol.

i know... what a dork...

but it's the right answer!

btw, randy got it right...

Answer 8

2(x+6)/(x+7)(x-5)(x+6)+
5(x-5)/(x+7)(x-5)(x+6)=
(2x+12+5x-25)/(x+7)(x-5)(x+6)=
(7x-13)/(x+7)(x-5)(x+6)

Answer 9

(7x-13)/(x+7)(x-5)(x+6)
(7x-13)/(xcubic+8xsquare-23x-210)

Answer 10

what r u try to find x or the answer