calculate the mass in (g) of NaCl that is present in 500.0 ml of a 0.900%(w/v) solution.?

Answer 1

mass / volume * 100 = percent

mass = percent * volume / 100

mass = 0.9 * 500 / 100 = 4.5 grams.

Answer 2

Molarity = moles/liter. If we'd like .5L of .2M answer, we'd want: .2 M = ? moles/ .5L Rearrange this equation to get .2*.5=moles, or .one million moles necessary. The molar mass of NaCl is fifty 8.forty 5 g/mol. We only multiply our moles necessary via the molar mass to get 5.80 5 grams of NaCl

Answer 3

since the mass of water is defined as 1 g/cc.
0.900% (w/v) = 0.009g/ml.
(.009 g/ml)(500 ml) = 4.5 g