Physics HW help?! (This is an emergency)?

Question

Hi, I have several question's and i am going to post each question separate so you can get extra points from teh other question's.

1.) A gamma ray emitted by an atom of this this isotope (Cobalt-60) has energy of 1.33 MeV (million electron Volts; leV=1.602x10^-19J). What is the frequescy (in Hz) and wave length (in m) of this gamma ray?

Answer 1

Using Planck's equation,
E = hv
Where E is the Energy in the photon of light, h is Planck's constant, and v is the frequency of the light.
Solving for v,
v = E / h
You are given E in the equation and h = 6.62606876 E-34 J s,
Just plug in and solve.

The same equation as above can be re-written as,
E = h * c / lambda
where lambda is the wavelength of the light and c is the speed of light in a vacuum.
c = 299,792,458 m/s

Answer 2

Use Planck's relation, E = hf. E is the energy of the wave, which you were given, h is Planck's constant 6.626 x 10^-34 J-s, and f is your unknown frequency. Once you find the frequency, you can calculate the wavelength, lambda, by simply taking velocity divided by frequency. Remember, the velocity is just the speed of light, c = 3 x 10^8 m/s, so lambda = c / f.