I'm assuming that you're talking about digits, and at is the result of concatenating a and t, not multiplying them. We set up an equation:
10t+a + a=10a+t
9t=8a
a=9/8t
Since a is a whole number, t must be divisible by 8, and so t must BE 8. Which means a is 9. Thus your equation is:
89 + 9 = 98
2006-10-17 15:17:54
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answer #1
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answered by Pascal 7
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If I understand you correctly, these letters aren't really variables. It's a numeric cryptogram. So, for starters, a + a is greater than 10, so a is 5 or greater. If a + a were not greater than 10, the first digit of the sum would still be t. Since t is the second digit of the sum of a and a, t must be even. Also, a is greater than t, because t in the tens place became a after addition. So t is even and a is greater than it, and also greater than or equal to 5. Though the magic of inspiration, it looks like this is 89 + 9 = 98. t is 8 and a is 9.
2006-10-17 22:16:45
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answer #2
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answered by DavidK93 7
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No:
ta + a = a(t+1)
If a=0,
ta+a=0 because we would have t(0) + 0 = 0
2006-10-18 07:53:17
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answer #3
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answered by bibi 2
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Any combination as long as "a" is 0.
ta = at : Therefore, adding "a" cannot change ta. The only number that can do this is 0.
2006-10-17 22:13:25
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answer #4
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answered by lightning_bug_x 2
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Because of the distributive quality of multiplication, AT = TA. That means that A=0 because TA +A = TA.
2006-10-17 22:13:32
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answer #5
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answered by Anonymous
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True only if a = 0
2006-10-17 22:14:50
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answer #6
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answered by harsh_bkk 3
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ta always equals at (commutative law for multiplication), so only zero can be added to one side and have it still equal to the other, i.e. a has to be zero (ta + zero = at)
now, if a=0, t can be any number
2006-10-17 22:12:41
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answer #7
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answered by Anonymous
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No.
ta + a = a * (t+1)
ta + a = at only at zero.
2006-10-17 22:13:35
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answer #8
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answered by EamsMan 1
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a=0, t= any number
I don't know what some of these people are talking about, but my answer is simple and correct.
2006-10-17 22:11:54
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answer #9
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answered by Anonymous
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