English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories
3

Help please?

Each letter represents a number from 0-9

2006-10-17 15:09:29 · 9 answers · asked by Christina M 2 in Science & Mathematics Mathematics

9 answers

I'm assuming that you're talking about digits, and at is the result of concatenating a and t, not multiplying them. We set up an equation:

10t+a + a=10a+t
9t=8a
a=9/8t
Since a is a whole number, t must be divisible by 8, and so t must BE 8. Which means a is 9. Thus your equation is:

89 + 9 = 98

2006-10-17 15:17:54 · answer #1 · answered by Pascal 7 · 2 0

If I understand you correctly, these letters aren't really variables. It's a numeric cryptogram. So, for starters, a + a is greater than 10, so a is 5 or greater. If a + a were not greater than 10, the first digit of the sum would still be t. Since t is the second digit of the sum of a and a, t must be even. Also, a is greater than t, because t in the tens place became a after addition. So t is even and a is greater than it, and also greater than or equal to 5. Though the magic of inspiration, it looks like this is 89 + 9 = 98. t is 8 and a is 9.

2006-10-17 22:16:45 · answer #2 · answered by DavidK93 7 · 1 0

No:

ta + a = a(t+1)

If a=0,
ta+a=0 because we would have t(0) + 0 = 0

2006-10-18 07:53:17 · answer #3 · answered by bibi 2 · 0 0

Any combination as long as "a" is 0.

ta = at : Therefore, adding "a" cannot change ta. The only number that can do this is 0.

2006-10-17 22:13:25 · answer #4 · answered by lightning_bug_x 2 · 0 2

Because of the distributive quality of multiplication, AT = TA. That means that A=0 because TA +A = TA.

2006-10-17 22:13:32 · answer #5 · answered by Anonymous · 0 2

True only if a = 0

2006-10-17 22:14:50 · answer #6 · answered by harsh_bkk 3 · 0 2

ta always equals at (commutative law for multiplication), so only zero can be added to one side and have it still equal to the other, i.e. a has to be zero (ta + zero = at)

now, if a=0, t can be any number

2006-10-17 22:12:41 · answer #7 · answered by Anonymous · 0 2

No.

ta + a = a * (t+1)

ta + a = at only at zero.

2006-10-17 22:13:35 · answer #8 · answered by EamsMan 1 · 0 2

a=0, t= any number

I don't know what some of these people are talking about, but my answer is simple and correct.

2006-10-17 22:11:54 · answer #9 · answered by Anonymous · 0 2

fedest.com, questions and answers