Probability part 3!.........?

Question

ok only 2 more questions needing 2 good answers!

two number cubes with faces marked 1 through 6 are rolled...

A) Find the (P) that the sum of the numbers rolled is even or 7

Next question

B) Find (p) that the numbers rolled have a sum that is odd or less then 6

CMON!

Answer 1

Figure out all the combinations (there should be 36 combinations) and highlight the ones that sum to 7:
1 1 = 2
1 2 = 3
1 3 = 4
1 4 = 5
1 5 = 6
1 6 = 7*
2 1 = 3
2 2 = 4
2 3 = 5
2 4 = 6
2 5 = 7*
2 6 = 8
3 1 = 4
3 2 = 5
3 3 = 6
3 4 = 7*
3 5 = 8
3 6 = 9
4 1 = 5
4 2 = 6
4 3 = 7*
4 4 = 8
4 5 = 9
4 6 = 10
5 1 = 6
5 2 = 7*
5 3 = 8
5 4 = 9
5 5 = 10
5 6 = 11
6 1 = 7*
6 2 = 8
6 3 = 9
6 4 = 10
6 5 = 11
6 6 = 12

For the first question, 6 of the 36 combination sum to 7, so the probability is 6/36 or 1/6.

Now do the same but highlight the ones less than 6 (not 6) or odd:
1 1 = 2*
1 2 = 3*
1 3 = 4*
1 4 = 5*
1 5 = 6
1 6 = 7*
2 1 = 3*
2 2 = 4*
2 3 = 5*
2 4 = 6
2 5 = 7*
2 6 = 8
3 1 = 4*
3 2 = 5*
3 3 = 6
3 4 = 7*
3 5 = 8
3 6 = 9*
4 1 = 5*
4 2 = 6
4 3 = 7*
4 4 = 8
4 5 = 9*
4 6 = 10
5 1 = 6
5 2 = 7*
5 3 = 8
5 4 = 9*
5 5 = 10
5 6 = 11*
6 1 = 7*
6 2 = 8
6 3 = 9*
6 4 = 10
6 5 = 11*
6 6 = 12
I think I counted 22, so the probability a sum is odd or less than 6 is 22/36 = 11/18

Answer 2

there are total 36 conceivable effects at the same time as 2 dice are rolled. journey A: effects with the sum being odd (3, 5,7,9,11) are 2+4+6+4+2 = 18 journey B: effects with the sum being below 6 (2,3,4,5) are: a million+2+3+4 = 10 Even A intersection B: effects with sum being odd and below 6 (3,5): 2+4 = 6 P(AUB) = P(A) + P(B) - P (A intersection B) P(AUB) = 18/36+ 10/36 - 6/36 P(AUB) = 11/18

Answer 3

A, chance of rolling a seven is 1/6
im too bored to finish