2006-10-17 14:13:14 · 6 answers · asked by antwone 1 in Science & Mathematics ➔ Mathematics
Original equation.
x - 2√x = 0
Factor out a common √x:
√x (√x - 2) = 0
A product is zero, if either is zero.
So either:
√x = 0
or
√x - 2 = 0
From here it is easy to see that:
x = 0
or
√x = 2
x = 4
So the solutions are x = 0 or x = 4
A graph of the equation is given below where you can confirm your answers.
2006-10-17 14:17:46 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
Slightly easier way: let y = sqrt(x), then the equation is y^2 - 2y = 0. The answers for this clearly are 0 and 2, so y = sqrt(x) = 0 or 2, x = 0 or 4.
2006-10-17 21:33:21 · answer #2 · answered by sofarsogood 5 · 0⤊ 0⤋
x = 2sqtx
x/sqtx = 2
sqtx = 2
x = 4
also x = 0 works
2006-10-17 21:24:55 · answer #3 · answered by banjuja58 4 · 0⤊ 0⤋
2 - 2sqt x = 0
-2sqt.x = -2
sqt x = 1
(sqt x)^2 = (1)^2
x = 1
Answer: x= 1
2006-10-17 21:21:15 · answer #4 · answered by frank 7 · 0⤊ 1⤋
x-2sqt.x=0 add 2sqrt(x) to each side
x=2sqrt(x) divide each side by sqrt(x)
sqrt(x)=2
x=4
also
x=0 since (0-2*sqrt(0)=0
2006-10-21 17:04:28 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋
then: x = 2sqrt(x)
then x = 0, and x = 0.5
2006-10-17 21:18:25 · answer #6 · answered by Doc_Cain 1 · 0⤊ 0⤋