Physics invloving de broglie wavelength?

Question

A 9.0 GeV electron has the same De Broglie wavelength as a high energy proton. What is the kinetic energy proton?


How do u solve this problem

Answer 1

lambda = h/mv

Since lambda (wavelength) is the same for both particles and h is a constant,

mv (proton) = mv (electron)

You know the masses, solve for the velocity of the proton.

Kinetic energy is 1/2 mv^2.

Aloha

Answer 2

For a particle, the total energy is defined as E=Gamma*m*c^2 Where m is mass c is the speed of light and Gamma is 1/(1-V^2/c^2)^(1/2) We can also relate the energy to planck's constant, and the frequency of the particle. E= h*f But, for any wave, we can write that v=lambda*f, so f=v/lambda h*v/lambda=m*c^2/(1-v^2/c^2)^(1/2) lambda= h*v*(1-v^2/c^2)^(1/2)/(m*c^2) And there you have it. Now, just plug and chug. Hope this helps.

Answer 3

I do not believe that the problem has a solution because its not true that the proton has the same wavelenght as the electron.