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Algebra 1

2006-10-17 13:23:53 · 10 answers · asked by Anonymous in Education & Reference Homework Help

10 answers

if your supposed to simplfy, your done
you can't add 3x and 5y together

2006-10-17 13:28:09 · answer #1 · answered by xxcowsgomoo724xx 2 · 0 0

you are supposed to make the 5y alone so first subtract a 3x from both sides so it will become 5y= 7-3x. then divide by 5 so it becomes y=7/5 -3x/5. you can also reduce it lower but I think if you leave it like that its also fine. learn to do it yourself is the only way to do.

2006-10-17 20:35:01 · answer #2 · answered by Lala 4 · 0 0

depends on what the problem tells you to do. To put it in y=mx+b form:
1. Subtract 3x from both sides
2. divide both sides by 5
3. Switch -3x and +7
You get: y= -3/5x+7/5

2006-10-17 20:34:13 · answer #3 · answered by Mixedbrunette 3 · 0 0

subtract 3x from both sides giving 5y= 7-3x
divide both sides by 5
the aswer is y = -3/5x+7/5
if what you're looking for is to solve for y

2006-10-17 20:27:22 · answer #4 · answered by lmnop9879234 2 · 0 0

im in algebra 1 too so dont 100% trust me lol

3x+5y=7

add 3x+5y=8xy=7

then divide 7 by 8

which in decimal form is .875

2006-10-17 20:26:48 · answer #5 · answered by Anonymous · 0 1

What are you trying to do with the problem? You can't with 2 unknown variables unless some other information is given.

2006-10-17 20:31:24 · answer #6 · answered by Justin A 3 · 0 0

What is the question? Solve for y? Solve for x? You haven't given enough information as to what you really want done with this equation.

2006-10-17 21:23:39 · answer #7 · answered by LARRY R 4 · 0 0

To solve this problem another equation must be given.If you treat this as an inequation,the answers will be innumerable and inequations is not in your syllabus ,I think

2006-10-18 09:40:55 · answer #8 · answered by alpha 7 · 0 0

depends on what you're asked to do in the problem

2006-10-17 20:32:36 · answer #9 · answered by Meghan T 3 · 0 0

re check your question.

2006-10-17 20:31:54 · answer #10 · answered by savio 4 · 0 0

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