ok first off: 60degrees = pi/3 (in radians)
tan (-60degrees) = sin (-60degrees)/ cos (-60 degrees)
= root(-3)/2 / (-1/2)
= root(3) aka sqaure root of 3
cot (-60degrees) = cos (-60degrees)/ sin (-60 degrees)
= (-1/2) / root(-3)/2
= root(3)/3 aka square root of 3 over 3
yea, i know fo sho that dis is rite....and your welcome, i got the PSAT's 2morrow to study for....
2006-10-17 12:29:00
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answer #1
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answered by d29061 2
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the first step you must do is figure out what the reference angle is. Since you have an angle in the 4th quadrant, your reference angle is -theta. So in your case your reference angle is -(-60) = 60 degrees. The tangent of 60 degrees is the same thing as the sin(60 degrees) / cos(60 degrees). The sin(60) and the cos(60) come from a 30 - 60 - 90 triangle and the unit circle. The sin(60) = sqrt(3)/2 and cos(60) = 1/2....so tan(60) = sqrt(3)/2 / 1/2 = sqrt(3).
So tan(60) = sqrt(3).
But tangent is negative in the 4th quadrant where your original angle is located, so tan(-60) = -sqrt(3).
The cotangent function is the reciprocal function of tangent, so to get cot(-60) all you do is take 1/tan(-60) = -1/sqrt(3).
2006-10-17 12:36:09
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answer #2
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answered by pecosbill2000 3
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Tan(-60) = -â3
Ctn(-60) = (-â3)/3
2006-10-17 12:26:20
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answer #3
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answered by Helmut 7
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just type into your calculator:
-60 and then the tangent button which is TAN.
same for the second one.
do you expect me to give you the actual answer?
2006-10-17 12:24:03
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answer #4
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answered by CuteMonkey 2
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refer tp your geometry twxt book
2006-10-17 12:26:23
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answer #5
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answered by Anonymous
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tan(-(60 degrees)) = -1.73205081
2006-10-17 12:25:57
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answer #6
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answered by DanE 7
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-1.732050808
.5
2006-10-17 12:24:21
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answer #7
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answered by 7
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