What is the oxidation number of P in Mg2P2O7?
of S in Na2S2O3?
of W in W(CN)4?
Thanks.
2006-10-17 12:00:30 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
oxygen is always 2- so do the oxygen first
07 = 2- x 7 = 14-
that means that P2 must cancel out the 14- and be 14+
since there are 2 P divide the 14+ by 2 and get 7+
oxygen is 2- and phosphorous is 7+
Na2S2O3
Na is always 1+ so 2 Na = 2+
O is 2- so O3 = 6-
put them together and get 4- so the S must cancel out 4-
2 S = 4+ so S = 2+
Ma 1+, S 2+, O 2-
W(CN)4
CN = 1- so 4 CN = 4-
that means W = 4+
CN = 1- and N = 3- so C is 2+
W 4+, C 2+, N 3-
2006-10-17 12:12:55 · answer #1 · answered by physandchemteach 7 · 0⤊ 1⤋
P in MgP2O7 should be +5
S in Na2S2O3 +2
W in W(CN)4 should be +1
2006-10-17 12:13:17 · answer #2 · answered by SMG 3 · 1⤊ 0⤋