If g(x)= x^2- 2x + 4
2006-10-17 11:46:19 · 7 answers · asked by waaah!!!? 1 in Science & Mathematics ➔ Mathematics
Replace g(x) with 199 and solve for x.
199 = x^2 - 2x + 4
Subtract 199 from each side
0 = x^2 - 2x - 195
Factor
0 = (x-15)(x+13)
x - 15 = 0 or x + 13 = 0
x = 15 or x = -13
2006-10-17 11:48:30 · answer #1 · answered by MsMath 7 · 0⤊ 0⤋
Well the above answers would be correct, but I can't help but noticing that they worked toward X by replacing g(x) with a number. In the end, the answer HAS to have 'g' back in it. And you can't have an either or proposition here. Either X is 15 or it's 13, but not both. So, we do agree:
199=x²-2x+4
Subt 199 from both sides.
0=x²-2x-195
195=x²-2x
So anyway, they got close above, but in the end....
X=15
and
G=13.2666 (remember g(x)=199, so g=199/x or 199/15=13.2666
2006-10-17 19:08:51 · answer #2 · answered by Marvinator 7 · 0⤊ 0⤋
199 = x^2 -2x +4
0 = x^2 - 2x -195
0 = (x-15)(x+13)
x = 15 or x = -13
2006-10-17 18:50:30 · answer #3 · answered by jg 2 · 0⤊ 0⤋
g(x)= x^2- 2x + 4=199
x^2-2x+4-199=x^2-2x-195
(x-15)(x+13)
so x=15
&
x=-13
check
(-13)^2-2*(-13)+4=169+26+4=199
15^2-2*15+4=225-30+4=199
2006-10-21 16:07:45 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
199=x²-2x+4
196=x²-2x+1
196=(x-1)²
x-1=±14
x=1±14
x=15 or x=-13
2006-10-17 18:49:23 · answer #5 · answered by Pascal 7 · 0⤊ 0⤋
Not gonna be a whole number. There's gonna be a decimal b'twix the digits.
2006-10-17 18:50:50 · answer #6 · answered by Anonymous · 0⤊ 1⤋
15,25
2006-10-17 18:47:54 · answer #7 · answered by Anonymous · 0⤊ 1⤋