After a snowstorm a girl and a boy decide to have a snowball fight. The girl uses a slingshot to shoot snowballs at the boy. Assume that the girl fires each snowball at an angle (-) from the ground and that the snowballs travel with an initial velocity of v0. HELP! I have no clue how to figure this one out!
2006-10-17 10:41:55 · 4 answers · asked by taintedlove463 1 in Science & Mathematics ➔ Physics
Think of the vertical travel independently: The initial upward velocity is v0sin(-) and is constantly accelerated at -g (taking up to be pos. and down neg.) Integrate the acceleration function to get the velocity and position functions (if you know calculus, otherwise just use the equations i give u):
v(t)=v0sin(-) - gt
h(t)=v0sin(-)t - 1/2gt^2+h0
where g is gravity and h0 is the ball's inital height above the ground.
Now set v(t)=0 (no vel. at top), solve for t and substitute this into h(t). Voila.
2006-10-17 10:56:58 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The tension of gravity (weight) appearing on an merchandise is a relentless tension in a relentless course .. as such the consequent replace it motives (ie .. acceleration) has a relentless value and course. Taking the acceleration as a results of gravity as 9.80 m/s² downwards .. it ability that throughout the time of the process the action the object's velocity is changing by way of 9.80m/s each and each sec in the downward course. For an merchandise shifting upwards this implies this is velocity is reducing by way of 9.80m/s² .. on a similar time as shifting downwards this is velocity is increasing by way of 9.80m/s². a) Taking upwards(?) as a results of fact the +ve course .. preliminary velocity u = +6.30 m/s?, acceleration a = -9.80m/s²?, very final vel v = 0 at max displacement d .. making use of v² = u² + 2ad 0 = (6.30)² + (2 x -9.80 x d) .. .. 19.60d = 6.30² .. .. d = 2.03m internet height above floor = 2.03m + a million.0m(preliminary place) .. ?3.03m b) Displacement at floor point d = -a million.0m (under preliminary place) u = +6.30m/s, a = -9.80m/s², finding very final vel v making use of v² = u² + 2ad v² = 6.30² + (2 x -9.80 x -a million) = fifty 9.29 .. v = ?fifty 9.29 .. ?v = 7.70 m/s (+ = downwards)
2016-12-08 16:20:58 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Conservation of energy. Convert the vertical component of kinetic energy into potential energy
2006-10-17 10:44:08 · answer #3 · answered by arbiter007 6 · 0⤊ 0⤋
Neither have I.
2006-10-17 12:31:49 · answer #4 · answered by quark_sa 2 · 0⤊ 0⤋