A 2.00 kg block is being pushed against a spring with negligible mass and force constant k=400 N/m, compressing it 0.22 m. When the block is released, it moves along a frictionless, horizontal surface and then up a frictionless inlcine with slope 37 degrees.
What is the speed of the block as it slides along the horizontal surface after having left the spring?
How far does the block travel up the incline before starting to slide back down?
2006-10-17 10:16:48 · 2 answers · asked by fender_tri 1 in Science & Mathematics ➔ Physics
I would use Hooke's Law. U = 1/2 k x^2 = the energy supplied to the object. Then you can find the velocity of the object, U = KE = 1/2 m v^2, and the height the object travels using conservation of energy, U = PE = mgh. Once you find the height, you use trig to find the length traveled up the incline, l = h/sin 37.
2006-10-17 12:36:43 · answer #1 · answered by daedgewood 4 · 0⤊ 0⤋
usually distance is measured in the two metres (m) or kilometers (km). Time could desire to be seconds (s) or minutes (m) velocity, is a mix of distance and time. E.g 60m/s (60 metres consistent with 2nd) does that help?
2016-10-19 21:42:48 · answer #2 · answered by templeman 4 · 0⤊ 0⤋