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a new car depreciate by 20% in its first year. Each succeding year its depreciate by 10% assume the car is still good working condition after ten years. if the car costs $25000, calculate the value of the car after 10 years

how in the world do I do this how do I start this question off?

thanks so much I don't get math so thanks for your help!

2006-10-17 09:58:59 · 8 answers · asked by Anonymous in Education & Reference Homework Help

8 answers

I don't want to answer the question for you, but here's how you look at it....

You buy the car for $25,000.

It goes down in value by 20% the first year (or it retains 80% of its value). That means that after the first year, the car is worth $25,000 * 80% or $20,000.

Now the car goes down in value by 10% after the second year (it retains 90% of it's value). That means that after the second year, the car is worth $20,000 * 90% or $18,000.

Keep going like this to determine what the value is after 10 years.

2006-10-17 10:08:46 · answer #1 · answered by Josh 2 · 0 0

There may be a simpler method, but what I did is I multiplied 25,000 x .20, to get 20% of it. Then I subtracted that number from 25,000 because you lose 20% of its value the first year. After that, I got 20,000. I multiplied 20,000 x .10 to get 10% of its value. then I subtracted that from 20,000. I got 18,000 after that. Then I multiplied 18,000 x .10 to get 10% of its value, and so on....

Each time I got a new estimated value, I marked how many years old it was. So but 18,000, it was 2 yrs old. 16,200, 3 yrs old, and so on....

Eventually the numbers became decimals in smaller spaces than actual cents, so I simply rounded my final answer to the nearest penny.

In the end I got $7,748.45 for the car after 10 years.

Im pretty sure this is the right answer.

2006-10-17 10:15:05 · answer #2 · answered by petwoip 1 · 0 0

Draw out a table for yourself... start with something like

Yr Value Less dep End of Yr Value
1 25000 -20% 20000
2 20000 -10% 18000
3 18000 -10% 16200

and so forth until you get to the end of year 10.

2006-10-17 10:05:21 · answer #3 · answered by Grover 3 · 0 0

At 0 yrs, the value is $25000
After 1 year it is only 80% of its first value = 0.8 * 25000 = $20000
After 2 years it is worth 90% of its value at 1 yr = 0.9*20000 = $18000
After 3years it is worth 90% of its value at 2 yrs= 0.9*18000 = $16200
After 4 years it is worth 90% of its value at 3 yrs = 0.9*16200 = $14580

Continue like this
After 5 yrs value =$13122
After 6 yrs value =$11809.80
After 7 yrs value =$10628.82
After 8 yrs value =$ 9565.93
After 9 yrs value = $ 8609.34
After 10 yrs value = $7748.40

2006-10-17 10:14:02 · answer #4 · answered by Anonymous · 0 0

ok, so use the 4 and six as a share. And use x as what number eggs you may desire to make 21 dozen. So, 4 eggs in line with 6 dozens = x eggs in line with 21 dozens. Now, merely pass multiply. 21x4=80 4 Sp, 80 4=6x make confident x is via itself, so divide via 6 on the two sides. bear in mind, in spite of the fact which you do to one area, you may do to the different. So divide 80 4 via 6 and you may get your answer! Sorry if it have been given difficult at some factors, yet i'm hoping it helped a minimum of somewhat!

2016-12-13 10:02:47 · answer #5 · answered by ? 4 · 0 0

25000*0.8*0.9^9 = 7748.409 $

Initial amonut times .8 is bcoz it will be left 80% after a 20% dep..., after that it will remain 90% every year, so multiply 9 times by .9

2006-10-17 10:10:56 · answer #6 · answered by ABCD 2 · 0 0

it is sam as the said above process...

after 10 yeras the car will be valued for an amount of around Rs. 7,5000

2006-10-17 10:11:49 · answer #7 · answered by rajesh1040 2 · 0 0

ok id strat off wit proroptions....if u no that kinda stuff...and go from there...im not the smartest at math but i do get those kinda ?ns

2006-10-17 10:03:41 · answer #8 · answered by Anonymous · 0 0

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