I don't want to answer the question for you, but here's how you look at it....
You buy the car for $25,000.
It goes down in value by 20% the first year (or it retains 80% of its value). That means that after the first year, the car is worth $25,000 * 80% or $20,000.
Now the car goes down in value by 10% after the second year (it retains 90% of it's value). That means that after the second year, the car is worth $20,000 * 90% or $18,000.
Keep going like this to determine what the value is after 10 years.
2006-10-17 10:08:46
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answer #1
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answered by Josh 2
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There may be a simpler method, but what I did is I multiplied 25,000 x .20, to get 20% of it. Then I subtracted that number from 25,000 because you lose 20% of its value the first year. After that, I got 20,000. I multiplied 20,000 x .10 to get 10% of its value. then I subtracted that from 20,000. I got 18,000 after that. Then I multiplied 18,000 x .10 to get 10% of its value, and so on....
Each time I got a new estimated value, I marked how many years old it was. So but 18,000, it was 2 yrs old. 16,200, 3 yrs old, and so on....
Eventually the numbers became decimals in smaller spaces than actual cents, so I simply rounded my final answer to the nearest penny.
In the end I got $7,748.45 for the car after 10 years.
Im pretty sure this is the right answer.
2006-10-17 10:15:05
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answer #2
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answered by petwoip 1
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Draw out a table for yourself... start with something like
Yr Value Less dep End of Yr Value
1 25000 -20% 20000
2 20000 -10% 18000
3 18000 -10% 16200
and so forth until you get to the end of year 10.
2006-10-17 10:05:21
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answer #3
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answered by Grover 3
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At 0 yrs, the value is $25000
After 1 year it is only 80% of its first value = 0.8 * 25000 = $20000
After 2 years it is worth 90% of its value at 1 yr = 0.9*20000 = $18000
After 3years it is worth 90% of its value at 2 yrs= 0.9*18000 = $16200
After 4 years it is worth 90% of its value at 3 yrs = 0.9*16200 = $14580
Continue like this
After 5 yrs value =$13122
After 6 yrs value =$11809.80
After 7 yrs value =$10628.82
After 8 yrs value =$ 9565.93
After 9 yrs value = $ 8609.34
After 10 yrs value = $7748.40
2006-10-17 10:14:02
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answer #4
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answered by Anonymous
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ok, so use the 4 and six as a share. And use x as what number eggs you may desire to make 21 dozen. So, 4 eggs in line with 6 dozens = x eggs in line with 21 dozens. Now, merely pass multiply. 21x4=80 4 Sp, 80 4=6x make confident x is via itself, so divide via 6 on the two sides. bear in mind, in spite of the fact which you do to one area, you may do to the different. So divide 80 4 via 6 and you may get your answer! Sorry if it have been given difficult at some factors, yet i'm hoping it helped a minimum of somewhat!
2016-12-13 10:02:47
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answer #5
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answered by ? 4
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25000*0.8*0.9^9 = 7748.409 $
Initial amonut times .8 is bcoz it will be left 80% after a 20% dep..., after that it will remain 90% every year, so multiply 9 times by .9
2006-10-17 10:10:56
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answer #6
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answered by ABCD 2
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it is sam as the said above process...
after 10 yeras the car will be valued for an amount of around Rs. 7,5000
2006-10-17 10:11:49
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answer #7
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answered by rajesh1040 2
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ok id strat off wit proroptions....if u no that kinda stuff...and go from there...im not the smartest at math but i do get those kinda ?ns
2006-10-17 10:03:41
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answer #8
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answered by Anonymous
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