trying to help grandaughter with math homework.
2006-10-17 09:35:06 · 12 answers · asked by hun_eluv 1 in Science & Mathematics ➔ Mathematics
g+c=95
4g+2c=316
c=95-g
4g+2(95-g)=316
4g+190+2g=316
2g=316-190=126
g=63
c=95-g=95-63=32
check
2*32+4*63=64+252=316
32 chickens
63 goats
2006-10-17 09:40:26 · answer #1 · answered by yupchagee 7 · 16⤊ 0⤋
You would have 63 goats and 32 chickens.
63 X 4(goat legs)= 252
95-63=32
32 X 2(chicken legs)=63
252 + 64 = 316 legs
2006-10-17 16:45:10 · answer #2 · answered by Jody L 1 · 0⤊ 0⤋
this is a two variable, two equation problem.
G+C=95 (you have 95 Goats and Chickens)
4G+2C=316 (if we assume each Goat has 4 legs and each Chicken has 2)
then solve for G and C
2006-10-17 16:45:07 · answer #3 · answered by Mark 2 · 0⤊ 1⤋
32 Chickens, 63 goats
2006-10-17 16:47:51 · answer #4 · answered by billybob 1 · 0⤊ 0⤋
You would have 63 goats and 32 chickens.
2006-10-17 17:00:36 · answer #5 · answered by utnip123 2 · 0⤊ 0⤋
(63 goats and 32 chicken)
(suppose x=goats
y=chicken
so, x+y=95 and
4*x+2*y=316
x=95-y
now,
4(95-y)+2*y=316
380-4*y+2*y=316
380-316=2*y
64=2*y
64/2=y
y=32
x=95-32
x=63.)
you r doing a good job for grandson grandma.....
2006-10-17 16:46:46 · answer #6 · answered by Anonymous · 0⤊ 0⤋
63 goats x4 = 252 legs
32 chicksx2= 64 legs
___ _____
95 316
2006-10-17 16:46:47 · answer #7 · answered by lm050254 5 · 0⤊ 0⤋
95x goats + y chickens = 316
y chickens = 316/95xgoats
2006-10-17 16:37:20 · answer #8 · answered by snorkelman_37 5 · 0⤊ 0⤋
g + c = 95
4g + 2c = 316
4(95 - c) + 2c = 316
380 - 4c +2c = 316
-2c = -64
c= 32
95 - 32 = 63
Chickens = 32
Goats = 63
2006-10-17 17:39:55 · answer #9 · answered by stormey4 2 · 0⤊ 0⤋
Let the no.of goats =x
Let the no. of chickens=y
so, x+y=95---------------------(1st equation)
One goat has 4 legs and one chicken has 2 legs.
So, 4x+2y=316----------------(2nd equation)
Solve both the equations and you will get the following answr:-
x=no.of goats=63
y=no. of chickens=32
2006-10-17 16:49:14 · answer #10 · answered by sk 2 · 0⤊ 0⤋