2006-10-17 08:31:01 · 3 answers · asked by Erin H 1 in Science & Mathematics ➔ Chemistry
Well Im not too sure how to do this but I'll take a stab at it:
5g Fe2O3 x (16g Oxygen / 159.69g Fe2O3) = 0.5 grams of Oxygen
However if you do 48 grams of oxygen instead of just 16 (because there are 3 Oxygen atoms present in Fe2O3) then you would get:
5g Fe2O3 x (48g Oxygen / 159.69g Fe2O3) = 1.5 grams of Oxygen.
So, you decide which way is right....if either of them are! lol. Good luck!
2006-10-17 09:10:15 · answer #1 · answered by BeC 4 · 0⤊ 0⤋
in 160(the mass of Fe2O3) grams of Fe2O3,there R 48 grams of Oxygen...Now that we have 5.0 grams there will be1.5 grams!
2006-10-17 16:19:25 · answer #2 · answered by NaZaniN e NaZaniN 1 · 0⤊ 0⤋
Molecular mass of Fe2O3 = 159.68 g/mol
% of Oxygen in Fe2O3 = (48 g (three oxygens)/159.68 g)x100%
=0.3006 x 100 % = 30.06%
grames of Oxygen In 5g of Fe2O3 = (5 g) (30.06%) = 1.503 g
That´s it!
Good luck!
2006-10-17 16:11:12 · answer #3 · answered by CHESSLARUS 7 · 0⤊ 0⤋