2006-10-17 07:38:03 · 5 answers · asked by BOISESTATEFAN208 1 in Science & Mathematics ➔ Physics
Neither.
It is available power (volts*amps) that kills you. Something that can provide high voltage (or high current) yet only can provide a small amount of power will not be able to kill you at all.
When people say, "It's not the volts that kill you; it's the amps," they probably mean that for a given voltage, if the current is restricted to be very low, it's not going to hurt you. It's only when the current is allowed to get high (again, for a GIVEN voltage). However, for a given voltage, this is the same thing as saying that the power available will be high.
The average person has never seen a current source, and so few people imagine a source that provides a steady current and varies the voltage. These devices exist and are used in electrical applications. With these, you could similarly say that "It's not the amps that kill you; it's the volts," implying that for a given current, it will only hurt you if the voltage delivered to you is high. In this case, it still isn't about the volts or the amps. It's about their product: the power.
2006-10-17 08:41:37 · answer #1 · answered by Ted 4 · 0⤊ 0⤋
Not at all clear what you want. When you say "4 rechargeable batteries" are you meaning 12v? or 1.2v (per cell)? If they are 1.2v then series connection will give you a 4.8v battery. This you could charge using a standard voltage regulator. However, charging four 12v batteries is an entirely different matter. Getting adequate current sharing will be the problem. You could use four low dropout regulators. Possibly the LP2953A from National? You may need current boosting. Depends on the current that the panel can supply. A standard voltage regulator such as the LM317 could do the remaining charging for you. They are very robust and will give you about 1.0 Amps (small heatsink - TO220) and 2.3 (large heatsink - TO3) Amps and are overload limited.
2016-05-22 09:02:34 · answer #2 · answered by ? 4 · 0⤊ 0⤋
The severity of electric shock depends primarily on the level of current passing through the body and the frequency of the current.
Electric shock from 60-hertz electric power becomes noticeable at currents of 1 to 10 milliamperes and may induce ventricular fibrillation at currents of 60 to 200 milliamperes. Voltage differential is crucial because it is an electric voltage across the body that induces current to flow through the body.
If you are working near a power line, your primary concern should be to keep a high impedance (either adequate air distance or adequate insulation) between you and a voltage differential (between the line and ground or between phases).
- An electric power engineer
2006-10-17 08:32:19 · answer #3 · answered by Deep Thought 5 · 0⤊ 1⤋
According to the Eng. Manuel current between 100 to 200 Milli amps through the chest cavity will cause the heart to fibulate. less might make u heart yourself . more than 200 ma. will cause burns. The voltage is the pressure that is required to force the current through the body. Be careful
2006-10-17 09:11:16 · answer #4 · answered by JOHNNIE B 7 · 0⤊ 0⤋
Voltage doesn't kill you. Amperage does.
Amps, if i remember correctly, is a measure of the current flowing through something
Voltage is a measure of electrical potential
2006-10-17 08:41:57 · answer #5 · answered by shinobisoulxxx 2 · 0⤊ 0⤋