Calculate pH for the solution, check my work please?

Question

check my answer and sig figs please

Calculate the pH of the solution below. Show chemical equations for all equlibria involved. Include complete dissociations whenever necessary.

0.55M ammonium choride and 0.80 M ammonia.

okay I had a Pkb of 4.76, I changed this to Kb = 1.7 x 10^-5

NH4CL ---H20---> NH4+ Cl-

all of these are .55M

NH3+H20<--> NH4+ + OH-

okay I have the Molarity of NH4+ and NH3 now

the ICE method gives an equation of (0.55+x)(x)/(0.80-x)=
1.7x10^-5

x= 2.5x10^-5 = [OH-]
change to pOH by -log = 4.60 pOH 14-4.60 = 9.40 = PH

so pH = 9.40

Answer 1

Absolutely correct!! Congratulations