when an equation is formed from a proportion why we need constant of proportionality(k).f=kma what is use of k

Question

please explain in brief

Answer 1

f=kma: f=ma doesn't need a constant of proportionality. These variables are defined so that f is equal to, not just proportional to, ma.

But, say you're in a grocery store putting cans of soup in a weight-free basket. One can isn't very heavy. 2 cans weigh twice as much. In fact the weight is proportional to the number of cans in the basket. But how much does it weigh? In pounds, or newtons, not cans? Well that's where a constant of proportionality comes in. It could convert number of cans to weight for you.

Anopther example a little more scientific in nature. The gravitational attraction between mass m1 and mass m2 is directly proportional to the product of their masses and inversly proportional to the square of the distance between them. This is a proportioinal relationship called Newton's law of universal gravitation. You could do the math but it didn't give you force in Newtons or pounds. It just allowed comparison with other results. About 100 years later, Lord Cavendish did careful measurements and determined a value for G the constant of proportionality for this relationship.
F = G*m1*m2/d^2
The value of G has since been revised after more careful measurements. The constant of proportionality for your basket of soup cans would be determined by weighing a typical can.

Answer 2

Proportional mean in proportion. In other words the graph of f vs a should be a straight line if f is proportional to a. The slope of the graph or the constant of proportionality is then km in the above equation. It turns out that in Newtons second law k = 1.

Answer 3

when we say "F is proportional to m" it means that the ratio of Fis to m is a constan. in other words they are equal only if all other factors affecting F are made unity.
for force by expts its known that "F is proportional to m" and "F is proportional to a". We define the unit of force in such a way that if 1kg mass is acc to 1 m/s(sq) the force is 1 newton.

Answer 4

in accordance to my mum, the quadratic formula is x= -b +/- ?b^2-4ac¯ .... ____________ ........ 2a consequently if a mode is sq.-rooted, it must be constructive and consequently must be more advantageous than 0, however the values are. For B, replace the values into that equation and sparkling up it regularly. you ought to get 2 conceivable values for ok. desire this helps. R

Answer 5

to determine the multiplier for resultion in 'f'.
=P