need help not good at math
2006-10-17 04:04:00 · 8 answers · asked by icandi22 1 in Science & Mathematics ➔ Mathematics
Put all terms on one side, try to replace the sum by products.
5x^2 - 15x = 0
x (5x-15) = 0
A product is nul if any of its factor is nul, thus:
x = 0
OR
x-15 = 0 <=> x = 15
2006-10-17 04:40:00 · answer #1 · answered by rvrusse 2 · 0⤊ 0⤋
You got to solve 5x^2=15x
Move 15x to the other side of = and put 0 on the right side of =
5x^2 -15x = 0
Then factorize
5x (x-3) = 0
Then solve separatly
5x = 0 or x - 3 = 0
5x/5 = 0/5 x = 3
x = 0
The answers are x = 0 or x = 3
2006-10-17 07:41:01 · answer #2 · answered by Roxy 2 · 0⤊ 0⤋
First transpose 15x to the left side:
5x^2-15x=0 (We change the sign when we transpose
a term.)
By investigation we can see that 5x is a factor of both terms, so we factor it out by dividing each term by 5x:
5x(x-3)=0
x has 2 values based on the above. The first value we
can get by equating the factor 5x to 0, or
5x=0
Divide each side by 5:
x=0/5
=0 (0 divided by any number equals 0).
The other factor is (x-3). We also equate this to O.
x-3=0
Transpose -3 to the right:
x=3.
2006-10-17 04:30:32 · answer #3 · answered by tul b 3 · 0⤊ 0⤋
Move 15x to the left side of the equation by subtracting.
So you will get
5x^2-15x = 0
Now factor out 5x from both terms.
5x(x-3) = 0
Now set set each factor equal to zero and solve.
5x = 0 and x-3 = 0
Hope this helps. Good Luck.
2006-10-17 04:20:33 · answer #4 · answered by SmileyGirl 4 · 1⤊ 0⤋
5x^2=15x
divide both sides by x:
5x = 15
divide both sides by 5:
x = 3
2006-10-17 04:13:31 · answer #5 · answered by Jabberwock 5 · 0⤊ 0⤋
5x^2 - 15x = 0
5x(x-3)=0
x=3 or x= 0
2006-10-17 04:12:50 · answer #6 · answered by Triathlete88 4 · 0⤊ 0⤋
5x^2-15x=0
5x(x-3)=0
either x=0 or x=3
2006-10-17 04:11:55 · answer #7 · answered by alam_1209 1 · 1⤊ 0⤋
5x^2=5x
-5x=-5x
5x^2-5x
(5x^2-5x+0)/ 5
X^2-x+0
(x+1)(x+0)
x= -1 or 0
2006-10-17 04:12:12 · answer #8 · answered by Pwnzer 4 · 0⤊ 1⤋