1)3 g
2)30 g
3)300 g
4)3000 g
2006-10-17 03:48:56 · 6 answers · asked by Shodan 2 in Science & Mathematics ➔ Physics
2)30g approx
actually it is 27.9g
sun's surface gravity=273.95 m s-2
2006-10-19 03:46:24 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You can use the mass and radius of the sun for this, but understand that there really is no 'surface of the sun' to stand on. The sun is an extremely hot ball of gas and you would need to walk on water before you could stand on the sun.
2006-10-17 04:06:43 · answer #2 · answered by resurrection_of_t_o 2 · 0⤊ 0⤋
g=G*M/R^2
where
G is a constant equal to 6.67*10^-11 N*m^2/kgr^2
M is the mass of the source of the gravitational field
R the distance from its center (if we are discussing the case of the surface then R equals the planet's or star's radius).
So all you have to do is find the values for M and R in the case of the sun and there you have it!
2006-10-17 04:06:04 · answer #3 · answered by fanis t 2 · 0⤊ 0⤋
u will need to use the formula g=GM\r*r
where G is a constant (6.67*10power 11,r is radius of the sun.it is close to 30 g
2006-10-17 04:12:12 · answer #4 · answered by the challenger 1 · 0⤊ 0⤋
2) 30g is the closest answer. It should really be 27.
2006-10-17 04:04:20 · answer #5 · answered by campbelp2002 7 · 0⤊ 0⤋
hey why are you going to visitun surface
2006-10-17 19:37:41 · answer #6 · answered by Anonymous · 0⤊ 0⤋