An aircraft has a take off velocity of 240 km/hr. What is the length of the runway needed at the airport if the average accelararation of the aircraft along the ground is 2.5 m/sec^2?
1) 90m
2) 490m
3) 980m
4) 9800m
2006-10-17 03:43:58 · 10 answers · asked by Shodan 2 in Science & Mathematics ➔ Physics
V = At
where V = 240 km/hr
A = 2.5 m/s
solve for t.
Then use X = 1/2 A t^2
You know A and t, solve for X (take-off roll distance, I get 4610 meters, so the runway better be longer than that.)
Answer would be 9800 m.
Aloha
2006-10-17 03:55:04 · answer #1 · answered by Anonymous · 0⤊ 0⤋
When a body is accelerated at a constant rate with zero initial velocity, the equations describing its kinematic state are the following:
v=a*t (1)
s=(1/2)*a*t^2 (2)
where
v is the velocity acquired at time t and a the constant acceleration.
Solving (1) for time we get t = v/a
Combining with (2) we get
s=(1/2)*a*(v/a)^2 ->
s=v^2/(2*a)
Using the values provided (taking care of course to convert the speed from km/hr to m/sec) we get
s=888.89 m (an approximate value)
So we may say that the length of the runway must be at least 889 m.
2006-10-17 04:13:15 · answer #2 · answered by fanis t 2 · 0⤊ 0⤋
There is more to runway design than just physics. The full runway length must be 1.15 times the length required for take-off -- for safety.
After that, clearway is provided.
In fact, the length of runway is even much larger than that. Runway length is calculated considering the case if aircraft engine fails and it has to abort takeoff !
2006-10-24 19:45:47 · answer #3 · answered by Ankit 2 · 0⤊ 0⤋
U=initial velocity=0km/hr
V=final velocity=240km/hr=66.67m/sec
a=acceleration=2.5m/sec
we Know V*V=U*U+ 2aS, Where S= distance
66.67*66.67=0+2*2.5*s
S=888.98m
2006-10-22 17:43:44 · answer #4 · answered by Manoj 1 · 0⤊ 0⤋
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2016-12-16 09:08:11 · answer #5 · answered by ? 3 · 0⤊ 0⤋
It will take you 96 seconds to get up to speed at rough average speed of 33 meters per second, or something like 3200 meters
2006-10-17 07:37:22 · answer #6 · answered by Nomadd 7 · 0⤊ 0⤋
Depends with the plane you are using(joke)
2006-10-21 23:44:52 · answer #7 · answered by Deepu 1 · 0⤊ 0⤋
the answer is 9800m
2006-10-17 04:07:50 · answer #8 · answered by the challenger 1 · 0⤊ 0⤋
980m
2006-10-24 06:26:04 · answer #9 · answered by Demon_sava 1 · 0⤊ 0⤋
888.89 ~ 980m
2006-10-18 10:45:24 · answer #10 · answered by Hemant 2 · 0⤊ 0⤋