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Let a be the number of digits of 2^2001, and let b be the number of digits of 5^2001. Compute the sum of digits, a+b. (Hint: 2^5=32 which is 2 digits and 5^5=3125 which is 4 digits, therefore the sum of the digits is 6)

i bet you cant figure this out~!

2006-10-17 03:36:05 · 6 answers · asked by Anonymous in Education & Reference Homework Help

6 answers

I always get counting wrong, but I got 2062.
Why would it ask such a boring problem? Why don't we bring back Hollerith cards for programming if we want to frustrate people?

2006-10-17 04:07:07 · answer #1 · answered by Bentley 4 · 0 0

As a test, 2^2 = 4 and 5^2 = 25 and 25 + 4 = 29, but (2+5)^2 = 49 which means 2^2001 + 5^2001 does not equal (2+5)^2001. But given the huge exponent, one has a sense that the answer is similarly simple. Question: I'm unfamiliar with SAT, can you use a calculator. If so, then the answer is duck soup. Just calculate the answer, which the calculator will probably give in scientific notation. Take the number which the scientific notation gives as the number of places to move the decimal place to the right to get the full answer and add 1 for the one number which is to the left of the decimal place.

2006-10-17 04:25:10 · answer #2 · answered by Anonymous · 0 0

The answer is 2002
It's always one more than the power you are taking 2 and 5 to. The reason is the follows:
When you multiply a number with x digits and another number with y digits, the total will always have x+y digits.
So, to figure out total number of digits in 2^n and 5^n just multiply them to get 10^n which has n+1 digits (obviously).

Another way to look at it: To get the number of digits in a number, just take log(10, n) and round up. So, your problem can be restated as:
log(10, 2^n) + log(10, 5^n) =
n*log(10,2) + n*log(10,5) =
n*(log(10,2) + log(10,5)) =
n*(log(10, 2*5)) =
n*(log(10,10)) =
n * 1
the extra one gets you from the rounding up.

2006-10-17 04:39:28 · answer #3 · answered by Leo Z 2 · 0 0

on the time she went into not common artwork, the mummy of the twins became traveling by utilising ability of boat. The older twin, Terry, became born first early on March 1st. The boat then crossed the international Date line (or any timezone line) and Kerry, the greater suitable youthful twin, became born on February the twenty eighth. In a bounce 3 hundred and sixty 5 days the greater suitable youthful twin celebrates her birthday 2 days earlier her older brother.. lmao!!!!! we've been given it on the comparable time.

2016-11-23 15:53:45 · answer #4 · answered by Anonymous · 0 0

is it 2002?

2006-10-17 03:52:14 · answer #5 · answered by Amy 4 · 0 0

2064

2006-10-17 04:00:57 · answer #6 · answered by Italian Mule 2 · 0 0

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