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a. a straight line
b. a vertical line
c. a parabola
d. decreasing

2006-10-17 03:16:08 · 10 answers · asked by Tony R 1 in Science & Mathematics Mathematics

10 answers

if the the first term is a-squared then it is a parabola since it a second order equation.

2006-10-17 03:25:12 · answer #1 · answered by mr.quark 2 · 0 0

a² + 8a + 16

= (a + 4)²

You should already have seen that, since it's a 2nd degree polynomial, it must be a parabola. But, if you "simplify" the expression the way I did, you can find out exactly how to graph it by yourself easily. First, draw a standard parabola (y = x²). Then, move the entire parabola itself 4 units to the left.

2006-10-17 04:06:11 · answer #2 · answered by عبد الله (ドラゴン) 5 · 0 0

First, you can factor the equation:

a2 + 8a +16 = 0
(a+4)(a+4) = 0

So, a = -4

When y = 0, then a will equal = - 4.

What if a is 0? then y will be 16.

This is a parabola because you have a positive exponent.

Regards,

Mysstere

2006-10-17 03:27:36 · answer #3 · answered by mysstere 5 · 0 0

Any equation that has a squared term as its highest power will be some kind of parabola.

A straight line is generally of the form y=mx+b or ax+by=c

A vertical line is x=some number

A decreasing graph can be lots of different things.

Hope this helps. Good Luck.

2006-10-17 03:55:24 · answer #4 · answered by SmileyGirl 4 · 0 0

each and every time an equation has an exponent means of two or larger it does no longer be a instantly line, vertical line, or lowering so it would want to go away "parabola because the answer. answer: Parabola

2016-12-04 22:18:07 · answer #5 · answered by hausladen 4 · 0 0

c) a parabola

considering you are treating y as a function of a, i.e. y=a^2+8a+16

2006-10-17 03:26:14 · answer #6 · answered by tsunamijon 4 · 0 0

any 2nd degree polymer function is a parabola.

2006-10-17 03:33:18 · answer #7 · answered by Dr. J. 6 · 1 0

c. a parabola

2006-10-17 04:27:53 · answer #8 · answered by alam_1209 1 · 0 0

c-a parabola

2006-10-17 03:50:51 · answer #9 · answered by Anonymous · 0 0

it would be B

2006-10-17 03:25:41 · answer #10 · answered by Janet 2 · 0 0

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