if the the first term is a-squared then it is a parabola since it a second order equation.
2006-10-17 03:25:12
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answer #1
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answered by mr.quark 2
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a² + 8a + 16
= (a + 4)²
You should already have seen that, since it's a 2nd degree polynomial, it must be a parabola. But, if you "simplify" the expression the way I did, you can find out exactly how to graph it by yourself easily. First, draw a standard parabola (y = x²). Then, move the entire parabola itself 4 units to the left.
2006-10-17 04:06:11
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answer #2
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answered by عبد الله (ドラゴン) 5
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First, you can factor the equation:
a2 + 8a +16 = 0
(a+4)(a+4) = 0
So, a = -4
When y = 0, then a will equal = - 4.
What if a is 0? then y will be 16.
This is a parabola because you have a positive exponent.
Regards,
Mysstere
2006-10-17 03:27:36
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answer #3
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answered by mysstere 5
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Any equation that has a squared term as its highest power will be some kind of parabola.
A straight line is generally of the form y=mx+b or ax+by=c
A vertical line is x=some number
A decreasing graph can be lots of different things.
Hope this helps. Good Luck.
2006-10-17 03:55:24
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answer #4
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answered by SmileyGirl 4
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each and every time an equation has an exponent means of two or larger it does no longer be a instantly line, vertical line, or lowering so it would want to go away "parabola because the answer. answer: Parabola
2016-12-04 22:18:07
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answer #5
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answered by hausladen 4
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c) a parabola
considering you are treating y as a function of a, i.e. y=a^2+8a+16
2006-10-17 03:26:14
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answer #6
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answered by tsunamijon 4
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any 2nd degree polymer function is a parabola.
2006-10-17 03:33:18
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answer #7
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answered by Dr. J. 6
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c. a parabola
2006-10-17 04:27:53
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answer #8
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answered by alam_1209 1
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c-a parabola
2006-10-17 03:50:51
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answer #9
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answered by Anonymous
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it would be B
2006-10-17 03:25:41
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answer #10
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answered by Janet 2
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