Is there a formula to work this out??
2006-10-17 02:34:02 · 8 answers · asked by Carrie W 1 in Science & Mathematics ➔ Physics
Assuming constant volume and equal temperatures, mass is proportional to pressure if you assume it is an ideal gas. In this case, the tire makes up virtually all of the weight, so you don't have enough information to solve the problem. If you said the tire weighs 61 kg and the air 1 kg at 110 psi, then you could calculate the new air weight as 1 kg * (500/110), then add back the tire weight.
2006-10-17 02:59:59 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You've gotten a lot of BAD answers!!
At 62 kg, that must be a very large tire (sorry, I'm a yank). I probably couldn't lift it. I assume a wheel is included in that - steel or aluminum? I'm going to have to make some guesses. More data would have helped. For example, mass of the tire both empty and at 110 psi. Or the volume of the air cavity. You can see that if the tire has extremely thick walls, leaving a relatively small volume for air, the amount of air crammed in there will have less affect on the total weight than if it is thin-walled. I'm going to assume the space in the tire is 20k in^3. (I used a formula for volume of a toriod: 2*pi^2*R*r^2.)
The density of dry air at STP is 1.293 kg/m^3. Since the pressure is in inches, let's convert this density to kg/in^3.
1.293 kg / (m^3 * (39.37 in/m)^3 = .02 g/in^3
Let's assume that the temperature is constant, so the formula you asked for is
p1*V1 = p2*V2.
We need to compare against the pressure at sea level to use this formula. The pressure figures you gave are measured as compared to pressure of free air - 15 psi. So convert the 110 psi figure to 125 psi. Then
15*V1 = 125*20k in^3
V1 = 167k in^3 is the volume of that air before you compressed it to get it into that tire. Multiply times the density.
167k in^3 * .02 g/in^3 = 3.34 kg
So the air in the tire at 110 psi added contributed 3 kg to the 62 kg. Increase the pressure to 500 psi and you can figure that the air is now about 15 kg. A 12 kg increase to about 74 kg.
Because of the guesses about the size of the tire, this is no better than a good guess. Incidentally, that's way too much pressure for a normal tire. It'd probably blow.
2006-10-17 11:43:30 · answer #2 · answered by sojsail 7 · 0⤊ 0⤋
If your accuracy level is rounding to the nearest kilo (which is suggested by the tire weighing 62kg) then the weiht is probably 62 kg. You are adding air to the inside of the tre, and air does not weigh that much, certainly not enough to alter the weight of a tire to any great extent.
2006-10-17 09:54:50 · answer #3 · answered by Theonlygolux 2 · 0⤊ 0⤋
it depends where the pressure is, is it on the inside of the tire pushing out, or outside the tire pushing it down and thus also the scale down...but then wouldn't that mean tha it weighs the same amount. Also, kg isn't weigfht, it's mass, weight is the pull of gravity on that mass, but that's also how they weigh weight in england, and usually when we talk about weight in common terms we're talking about mass. So...did that help at all? Sorry.
2006-10-17 09:51:48 · answer #4 · answered by Julie 3 · 0⤊ 1⤋
PRESSURE=force/area
110=62/area.
500=force/area, in both the cases area is same,so
110/500=62/force
Force=62*500/110
Force=281.82 kg.will the tyre weigh when increased to 500psi.
2006-10-17 10:03:25 · answer #5 · answered by Anonymous · 0⤊ 1⤋
Before it's possible to calculate that, you need to know the weight of the tire WITHOUT air, or with ambient pressure. Otherwise it's impossible to know what portion of the tire's weight is the tire itself and how much is from the air inside.
2006-10-17 10:11:33 · answer #6 · answered by poorcocoboiboi 6 · 1⤊ 0⤋
You have to give volume of the tyre that holds air.
2006-10-17 10:32:57 · answer #7 · answered by Trad 2 · 1⤊ 0⤋
i WOULD JUST DO A RATIO EQUATION:
62KG/110 psi = x KG/500 psi
x= 281.818 Kg
2006-10-17 09:49:36 · answer #8 · answered by nor2006 3 · 0⤊ 1⤋